Shell Programming and Scripting

Hi,

any idea how to extract alphabets alone in the string which contains numbers and alphabets. Thanks in advance!

Post sample data and desired output.

you may try something like this

Code:

echo "aB12Cd"  | tr -dc '[a-zA-Z]'

Here is the sample input: 1234567890 abc 1234
Alphabets inside the string could be of any length and i have some 70+ different patterns ( like abc or abc- or abc . ) in another file. I just want to check whether it matches any of those patterns. If so, i would like to extract the things before the pattern and after the pattern.

Thanks in advance!

So you just want to remove digits from the input file? If so, try this:

Code:

sed 's/[0-9]//g' infile > outfile

Thanks... But i would like to know how to extract the numbers which are present before the pattern and after the pattern.

Code:

echo "1234567890 abc 1234" | awk -F "[a-zA-Z]*" '{print $1 $2}'

if u have the character in a file then

Code:

awk -F "[a-zA-Z]*" '{print $1 $2}' sample.txt

where $1 will be before the pattern and $2 after the pattern