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Shell script regex help: accept only 3 file extensions

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# 1  
Old 11-12-2009
Question Shell script regex help: accept only 3 file extensions
This regex is supposed to accept files with extensions 270, 276, and "txt" only. Everything else should be discarded.

This is what I have. I'll spare you the rest of the code.
Code:
[..]
 ext =".[(27(0|6).txt)]\$"
 #ext =".[(27|0|6|.txt)]\$"
 #ext =".[27|0|6|.|txt]\$"
 #ext =".[27(0|6)|.txt]\$"

[..]
   for xfile in `ls $dir | grep "$ext" | xargs`; do
 [..]

The problem with my regex is that is accepting more than those 3 file extensions.

Any help is appreciated.
# 2  
Old 11-12-2009
This type of construct works for me, as an example:

Code:
me@www:/tmp# ls | egrep '27(0|6)\.txt$'
270.txt
276.txt

Edit: Nevermind... seems the poster wants only extensions \.270$ \.276$ and \.txt$ and not .*270\.txt etc... thanks Scrutinizer
# 3  
Old 11-12-2009
Hi,
Code:
egrep "\.(27[06]|txt)$"

should work
# 4  
Old 11-12-2009
thnx guys, I appreciate it.

now for one of the if-statements I have down the code...

what type of construct would help me get only these 4 file ext variants?
*.270
*.276
*.270.txt
*.276.txt

I'm trying this regex
Code:
ext="27[(0|6)|.txt]\$"; 
#ext = "(27[(0|6)]) | [.txt]\$";


but for some reason it doesn't accept:
270.txt
276.txt
# 5  
Old 11-12-2009
Code:
egrep "\.27[06](|\.txt)$"

-or-
Code:
egrep "\.27[06](\.txt){0,1}$"

should do the trick...
Last edited by Scrutinizer; 11-12-2009 at 05:36 PM..
# 6  
Old 11-12-2009
MySQL
Quote:
Originally Posted by Scrutinizer
[code]
Code:
egrep "\.27[06](\.txt){0,1}$"

should do the trick...
right on!! thnx, that one did it. It works like a charm.
# 7  
Old 11-12-2009
Code:
for xfile in $dir/*.27{0,6}{,.txt}; do
...

don't use ls to feed a for loop
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