to find the number of users logged in


 
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# 1  
Old 05-30-2007
hi

Hi,

can u say to display the number of users that logged before me.

thanks

Last edited by shanshine; 05-30-2007 at 06:01 AM..
# 2  
Old 05-30-2007
Try this..should work

who | awk '{print $1}'|uniq
# 3  
Old 05-30-2007
Hope this helps

Code:
 who | awk ' { print $1 }' | sort -ud

Thanks.
Nagarajan G
# 4  
Old 05-30-2007
Quote:
Originally Posted by ennstate
Hope this helps

Code:
 who | awk ' { print $1 }' | sort -ud

Thanks.
Nagarajan G
but it shows
+ who
+ awk '{ print $1 }'
+ sort -ud
these lines also.
# 5  
Old 05-30-2007
Code:
who | awk '{usr[$1]}END{for(i in usr)print i}'

# 6  
Old 05-30-2007
Quote:
Originally Posted by shanshine
but it shows
+ who
+ awk '{ print $1 }'
+ sort -ud
these lines also.
You have the -x option on (prints executed commands and their arguments).
To disable this option :
Code:
set +x

An example :
Code:
$ set -x
$ date
+ date
Wed May 30 09:40:54 DFT 2007
$ set +x
$ date
Wed May 30 09:41:01 DFT 2007
$

Jean-Pierre
# 7  
Old 05-30-2007
Quote:
Originally Posted by shanshine
but it shows
+ who
+ awk '{ print $1 }'
+ sort -ud
these lines also.
can u say to display the number of users that logged before me.
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