sed and maybe AWK


 
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# 1  
Old 10-16-2010
sed and maybe AWK

Hello
I would like to replace in a big file:

this
HTML Code:
000000001 260   L $$aVIENNA :$$bIAEA, 1988,$$c1988.
by this

HTML Code:
000000001 260   L $$aVIENNA :$$bIAEA,$$c1988.
As you see, the date into the second field is to be remove...
How can I do?
the patern could be this:
HTML Code:
, 1
and
HTML Code:
, 20
Thanks a lot
# 2  
Old 10-16-2010
Code:
 awk -F, '{print $1 FS $3}' file

# 3  
Old 10-16-2010
Code:
sed 's/,.*,/,/'

# 4  
Old 10-16-2010
Hi
ok it works, but in some case I have the second filed with the title with comas...
So the sed sed 's/,.*,/,/'drop the rigth part of the title...
Exemple:

000000001 260 L $$aVIENNA :$$bIAEA, SECOND INFO, 1988,$$c1988.
# 5  
Old 10-16-2010
Code:
sed 's/, [0-9]*,/,/'

# 6  
Old 10-16-2010
Code:
sed 's/[^,]*,\([^,]*$\)$/\1/' infile

Code:
awk -F, '{$(NF-1)=x}sub(FS FS,FS)' OFS=, infile


Last edited by Scrutinizer; 10-16-2010 at 01:46 PM..
# 7  
Old 10-16-2010
Hi Aia
thanks for the exemple...
It still don't works for all the records. Look this exemple:
Where SAN DIEGO is the first field (no problem with it)
and where ACADEMIC PRESS, INC.;1989;SAN DIEGO, CALIFORNIA 92101
is the second filed...

HTML Code:
SAN DIEGO;ACADEMIC PRESS, INC.;1989;SAN DIEGO, CALIFORNIA 92101
If I pass your script I have this:

HTML Code:
$$aSAN DIEGO :$$bACADEMIC PRESS, INC.,$$c1989.
SAN DIEGO, CALIFORNIA 92101 is missing then...
Maybe there is a way to get just 4 digits as a date?
I try this but it do not works:

HTML Code:
sed -i '/[0-9]\{9\} 260   L/s/, [0-9]\{4\},/,/g' biblio1.mrk_aleph_sec.dat
Thanks in advance if you have some idea.
Cheers
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