How to input "EOF" signal?


 
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# 1  
Old 05-04-2011
How to input "EOF" signal?

How to input "EOF" signal?
Code:
#include<stdio.h>
int main(int argc,char *argv[])
{
     int c,i;
     i=0;
    while((c=getchar()) != EOF )
    {
        if(c=='\n')
            ++i;
    }
     printf("%d\n",i);
}

How to input an "EOF" signal ? to gain the value of "i";Thanks.Smilie

Last edited by pludi; 05-04-2011 at 09:18 AM..
# 2  
Old 05-04-2011
I think in Unix ctrl + d will work
This User Gave Thanks to kumaran_5555 For This Post:
# 3  
Old 05-04-2011
in debian

I execute the program in Debian. It had no response when input "Ctrl D" and was interrupted when input "Ctrl Z" in terminal. Smilie How to print the value of i?
# 4  
Old 05-04-2011
Strange, Ctrl+D should have worked. With Ctrl+Z, you've sent the program into the background, suspending its execution, so there won't be any more output (check the output of ps -ef, and you'll see them floating around).
This User Gave Thanks to pludi For This Post:
# 5  
Old 05-04-2011
This is a program from K&R.

after executing you should type couple of lines as input, and then hit ctrl+D.

Then this will output number of lines you have entered.
This User Gave Thanks to kumaran_5555 For This Post:
# 6  
Old 05-04-2011
Thanks.I try it."Ctrl+D" worked.
By the way, for the first time, gcc shows
Code:
"linker input file unused because linking not done"

,what's meaning? Thanks in advance.
# 7  
Old 05-04-2011
post the gcc command you have executed.
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