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Shell Programming and Scripting

eleminate repated process names and get second column value

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# 1  
Old 01-01-2009
Lightbulb eleminate repated process names and get second column value
i want shell script who can eliminate those repeated process and get value of top process of second column.

Mark with red one only i want other repeated process should be eliminate but how? Help me out guys.


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# 2  
Old 01-01-2009
Try:

Code:
awk '{ if(a[$1]=="") {a[$1]=$2; print $1" "a[$1]; } }'  filename

# 3  
Old 01-01-2009
Code:
awk '!x[$1]++' filename

# 4  
Old 01-02-2009
Code:
#! /usr/bin/perl
open FH,"<a.txt";
while(<FH>){
	my @tmp=split(" ",$_);
	if(! exists $hash{$tmp[0]}){
		print $_;
		$hash{$tmp[0]}++;
	}
}
close FH;

# 5  
Old 01-02-2009
Idea:
See if your "ps" command has the "-H" (hierarchy) option .
Beware:
1) unix does not necessarily allocate process IDs in numeric order.
2) I have not noticed a process hierarchy with Oracle. On my system the parent process PPID for all Oracle processes is ID 1 (init). Yours may be different.
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