I have a typical requirement to find users having at least three occurrence in a log within an hour, and perform some action for that user. We have several steps, however I am kind of stuck here to accomplish the said requirement.
Basically, we need to find any user ( ie uid=xyz123), getting "SRCH=Q" in a particular connection have more than three occurrence within an hour. If you see the logs, they are related with "conn=13570".
In brief, here is the logic :
- Get the "SRCH=Q" occurence.
- Get the associated conn #, go back and get the bind user.
- Carrying bind user, search for "SRCH=Q" occurrence, if > 3, run add group command.
Let me know if we can get this via grep, sed or awk.
Thanks, JPrince
---------- Post updated 06-07-13 at 12:24 AM ---------- Previous update was 06-06-13 at 02:17 PM ----------
Hello,
Any reply on this?
JPrince
Last edited by johnprince1980; 06-06-2013 at 04:34 PM..
If you see the below logs, how can i search for "SRCH=Q", and then get the string in the same row "conn=13570", and perform another search to get "uid=xyz123" by looking up "conn=13570" and BIND String ( as mentioned in the first row).
I want to do this activity until I get three searches, and then store the user in a list.
awk 'FNR==NR {if ($0~"BIND") {split($8,s,"=|,");a[$3]=s[3]};if ($0~"SRCH=Q") b[$3]=$12;next} END { for (i in b) print b[i],i,a[i]}' file file
SRCH=Q conn=13570 xyz123
SRCH=Q conn=13572 xyz456
The intent here is to get the output only when there are 3 or more occurrences of search. When I run the code, it gives me an output even there are one occurrence.
Just a little help if possible
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