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# 1  
Old 06-03-2010
Error script help

HI All,

I am having a file with content

-rw-r----- 1 root system 0 Jun 03 01:50 /etc/name_v1
-rw-r----- 1 root system 0 Jun 03 01:50 /etc/name_v2
-rw-r----- 1 root system 0 Jun 03 01:50 /etc/name_v3

From this, i need find out only '/etc/name_v3' of the last line(last part of the last line). And need to store that value to a variable.

Thanks in advance
Renjesh Raju
# 2  
Old 06-03-2010
I don't understand your question very well but

Code:
grep "/etc/name_v3$" IN_FILE

shows only the line you want...
# 3  
Old 06-03-2010
Code:
VAR1=`tail -1 filename | awk '{print $NF}'`
echo $VAR1

# 4  
Old 06-03-2010
I gave just an eg.
I am not sure about the file content, all i need to do is to find the last part of the last line. I want a general way to find the particular content from the file.
# 5  
Old 06-03-2010
Hi.

Code:
$ sed -n "$ s|[^/]*||p" file1
/etc/name_v3

Code:
sed -n "$ s/.* //p" file1
/etc/name_v3

# 6  
Old 06-03-2010
I want to grep "name_v3" part only.
# 7  
Old 06-03-2010
The las solution will not work if the last is: /etc/var file name with spaces

Try with this:

Code:
tail -1 fichero1 | awk -F" " '{$1=$2=$3=$4=$5=$6=$7=$8="";OFS=" "}1' | sed "s/^ *\/etc\///"

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