Shell Programming and Scripting

Hello all,

I'm having trouble trying to get the output of a variable passed from an INFILE. Here is what i have so far.

/tmp/INFILE --- inside INFILE will be 2 or more filenames like so

/apps/opt/FTTP_`date '+%m%d%y'`.txt
/apps/opt/DSLFeed.`date '+%m%d%y'`.txt


--Here is just a simple script to get the information

for i in `cat /tmp/INFILE`

do

if [ -f "$i" ];then

echo "$i file found"
exit 0

else

echo "$i file not found"

fi

done

***Problem is i can't get the output to return the data in the file which would be FTTP_090707.txt****

All that returns is FTTP_`date '+%m%d%y'`.txt

Your help is greatly appreciated.

Thanks,

AC

Try:

Code:

while read fil1
do
   eval echo ${fil2}
done</tmp/INFILE|while read fil2
                          do
                              if [ -f "${fil2}" ]
                              then
                                  echo "${fil2} file found"
                              else
                                  echo "${fil2} file not found"
                              fi
                           done

(maybe you can get a better solution using eval)

Klashxx,

Thank you for your timely reply. The infile has lets say 2 records in that file.

/apps/opt/FTTP_`date '+%m%d%y'`.txt
/apps/opt/DSLFeed.`date '+%m%d%y'`.txt

when i'm specifing [ -f "$i" ]

i want it to return FTTP_090707.txt if the file is there. Now it's just listing FTTP_`date '+%m%d%y'`.txt

for some reason i don't know why the `date '+%m%d%y'`.txt will not pass to the variable.

Thanks,

AC