bitmap_parse_user(9) [centos man page]

BITMAP_PARSE_USER(9)					  Basic Kernel Library Functions				      BITMAP_PARSE_USER(9)

NAME

       bitmap_parse_user - convert an ASCII hex string in a user buffer into a bitmap

SYNOPSIS

       int bitmap_parse_user(const char __user * ubuf, unsigned int ulen, unsigned long * maskp, int nmaskbits);

ARGUMENTS

       ubuf
	   pointer to user buffer containing string.

       ulen
	   buffer size in bytes. If string is smaller than this then it must be terminated with a .

       maskp
	   pointer to bitmap array that will contain result.

       nmaskbits
	   size of bitmap, in bits.

DESCRIPTION

       Wrapper for __bitmap_parse, providing it with user buffer.

       We cannot have this as an inline function in bitmap.h because it needs linux/uaccess.h to get the access_ok declaration and this causes
       cyclic dependencies.

COPYRIGHT

Kernel Hackers Manual 3.10					     June 2014						      BITMAP_PARSE_USER(9)

BITMAP_ONTO(9)						  Basic Kernel Library Functions					    BITMAP_ONTO(9)

NAME

       bitmap_onto - translate one bitmap relative to another

SYNOPSIS

       void bitmap_onto(unsigned long * dst, const unsigned long * orig, const unsigned long * relmap, int bits);

ARGUMENTS

       dst
	   resulting translated bitmap

       orig
	   original untranslated bitmap

       relmap
	   bitmap relative to which translated

       bits
	   number of bits in each of these bitmaps

DESCRIPTION

       Set the n-th bit of dst iff there exists some m such that the n-th bit of relmap is set, the m-th bit of orig is set, and the n-th bit of
       relmap is also the m-th _set_ bit of relmap. (If you understood the previous sentence the first time your read it, you're overqualified for
       your current job.)

       In other words, orig is mapped onto (surjectively) dst, using the the map { <n, m> | the n-th bit of relmap is the m-th set bit of relmap
       }.

       Any set bits in orig above bit number W, where W is the weight of (number of set bits in) relmap are mapped nowhere. In particular, if for
       all bits m set in orig, m >= W, then dst will end up empty. In situations where the possibility of such an empty result is not desired, one
       way to avoid it is to use the bitmap_fold operator, below, to first fold the orig bitmap over itself so that all its set bits x are in the
       range 0 <= x < W. The bitmap_fold operator does this by setting the bit (m % W) in dst, for each bit (m) set in orig.

       Example [1] for bitmap_onto: Let's say relmap has bits 30-39 set, and orig has bits 1, 3, 5, 7, 9 and 11 set. Then on return from this
       routine, dst will have bits 31, 33, 35, 37 and 39 set.

       When bit 0 is set in orig, it means turn on the bit in dst corresponding to whatever is the first bit (if any) that is turned on in relmap.
       Since bit 0 was off in the above example, we leave off that bit (bit 30) in dst.

       When bit 1 is set in orig (as in the above example), it means turn on the bit in dst corresponding to whatever is the second bit that is
       turned on in relmap. The second bit in relmap that was turned on in the above example was bit 31, so we turned on bit 31 in dst.

       Similarly, we turned on bits 33, 35, 37 and 39 in dst, because they were the 4th, 6th, 8th and 10th set bits set in relmap, and the 4th,
       6th, 8th and 10th bits of orig (i.e. bits 3, 5, 7 and 9) were also set.

       When bit 11 is set in orig, it means turn on the bit in dst corresponding to whatever is the twelth bit that is turned on in relmap. In the
       above example, there were only ten bits turned on in relmap (30..39), so that bit 11 was set in orig had no affect on dst.

       Example [2] for bitmap_fold + bitmap_onto: Let's say relmap has these ten bits set: 40 41 42 43 45 48 53 61 74 95 (for the curious, that's
       40 plus the first ten terms of the Fibonacci sequence.)

       Further lets say we use the following code, invoking bitmap_fold then bitmap_onto, as suggested above to avoid the possitility of an empty
       dst result:

       unsigned long *tmp; // a temporary bitmap's bits

       bitmap_fold(tmp, orig, bitmap_weight(relmap, bits), bits); bitmap_onto(dst, tmp, relmap, bits);

       Then this table shows what various values of dst would be, for various orig's. I list the zero-based positions of each set bit. The tmp
       column shows the intermediate result, as computed by using bitmap_fold to fold the orig bitmap modulo ten (the weight of relmap).

       orig tmp dst 0 0 40 1 1 41 9 9 95 10 0 40 (*) 1 3 5 7 1 3 5 7 41 43 48 61 0 1 2 3 4 0 1 2 3 4 40 41 42 43 45 0 9 18 27 0 9 8 7 40 61 74 95
       0 10 20 30 0 40 0 11 22 33 0 1 2 3 40 41 42 43 0 12 24 36 0 2 4 6 40 42 45 53 78 102 211 1 2 8 41 42 74 (*)

       (*) For these marked lines, if we hadn't first done bitmap_fold into tmp, then the dst result would have been empty.

       If either of orig or relmap is empty (no set bits), then dst will be returned empty.

       If (as explained above) the only set bits in orig are in positions m where m >= W, (where W is the weight of relmap) then dst will once
       again be returned empty.

       All bits in dst not set by the above rule are cleared.

COPYRIGHT

Kernel Hackers Manual 2.6.					     July 2010							    BITMAP_ONTO(9)