Shell Programming and Scripting

Hi,

I've a filename of this format: "XXX_XXX_TXT.TAR.AS". Need to change the name into this format: "XXX_XXX.TAR.AS". This file resides in a directory. I'm ok with using the find command to search and display it.

Essentially I just need to replace the string "_TXT.TAR.AS" to ".TAR.AS". Is awk or sed the way to do it?

Thanks.

[QUOTE=chengwei;302199456]Hi,

I've a filename of this format: "XXX_XXX_TXT.TAR.AS". Need to change the name into this format: "XXX_XXX.TAR.AS". This file resides in a directory. I'm ok with using the find command to search and display it.

Essentially I just need to replace the string "_TXT.TAR.AS" to ".TAR.AS". Is awk or sed the way to do it?

Thanks.[/QUOTE
first do a find and store the files in a new file. Loop it and inside loop do this.

Code:

sed 's/XXX_XXX_TXT.TAR.AS/XXX_XXX.TAR.AS/' filename

With sed:

Code:

sed 's/\(.*\)_TXT\(.*\)/\1\2/'

With awk:

Code:

awk '{sub("_TXT","")}1'

Regards

The values XXX_XXX are actually timestamp dynamically generated, hence I do not know them in advance. How would I be able to combine with the find command to achieve this?

I did this:

Code:

find . -name "*_TXT.TAR.AS" -print -exec awk '{sub("_TXT.TAR.AS")}1' {} \;

and gotten the error messages:
What am I missing here?

Many thanks for the help.

Code:

find . -name "*_TXT.TAR.AS" -print|awk '{f=$0;sub("_TXT","");print "mv "f" "$0}'|sh

or:

Code:

find . -name "*_TXT.TAR.AS" -print |sed 's/\(.*\)_TXT\(.*\)/mv & \1\2/'| sh

Check the output before you pipe it to sh.

Regards

What does the "1" in awk command meant? How does it change into the string that I want?

Thanks!