Working on a job I was asked get a simple script to perform the following task and would like to ask for some help. I'm looking forward to learning more and diving deeper into the World of Open Source servers.
I need a script for a Unix server, using as few lines as possible, that generates a list of users that have active processes on a server and the number of processes for each of those users.
I know the basic scripting and syntax of creating structured code creation as I had to take a bunch of programming classes in college, and have created many batch apps in the command line world.
I'm assuming there is a show process command, and for some reason I want to say it's something like sho usr or close to that.
If it was commented out that would be really great too.
Would someone please be so kind to assist me or have an old one lying around?
Many thanks in advance for your consideration,
Mo-
echo -e "Name\t\tNo of Process"
for name in `users | tr ' ' '\n' |uniq`
do
count=`ps -U $name | wc -l`
let count=$count-1
echo -e "$name \t\t $count"
done
I understand most of what is happening, however could you let me know If I'm interpreting your example correctly?
ps, by itself, shows you information about only your processes. To learn more about all of the processes that are running, use the -ef options with the ps command.
I understand most of what is happening, however could you let me
know If I'm interpreting your example correctly?
Can you show me an example of your output? I'm at home and can't try it myself. I would be very appreciative.
I realize I'm being a pain, however If you can I'd be very happy.
Many thanks,
Mo-
---------- Post updated at 10:32 PM ---------- Previous update was at 10:16 PM ----------
If I was going to be contructing this in good form:
I thought it might look something like what I started below and commented out so even a newby like me can quickly look at it and see what is happening.
I like to have the output be formatted in a manner that is a little more self explanitory.
Can you let me know if I'm on the right track? Am I missing something fundamental? Am I doing something stupid? All assistance is most welcome.
Thanks,
Code:
#!/bin/bash
# Title........: serv_u_p
# Description..: Displays Server user and processes
# Author.......: Mo Ahten - TBD
# Contact......: moahten_____
# Last Modified: 03/01/10
#----------------------------------
# Begin script
$ ps –ef >> serv_u_p.txt
# End Script
Last edited by pludi; 03-02-2010 at 02:41 AM..
Reason: code tags, please!!!
echo -e "Name\t\tNo of Process"
for name in `users | tr ' ' '\n' |uniq`
do
count=`ps -U $name | wc -l`
let count=$count-1
echo -e "$name \t\t $count"
done
I get the users who have the processes by the command sequence "users | tr ' ' '\n' |uniq".The command "users" will give the user name with some process.Then I align the output and get the result as all the users.
like ,
karthigayan
aaa
bbb
ccc
....
....
The using the user name I get the number of process running for the users by using the "ps -U $name | wc -l".
The reason for removing the count is by one is that the ps will give the output with its header.
Here is the output ,
Code:
Name No of Process
karthigayan 43
aaa 36
bbb 57
ccc 39
....
....
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