UNIX for Dummies Questions & Answers

I have a file in which I need to search if a new line character exists on the last line in the file. Please let me know how can I achieve it using Unix commands?

Code:

awk 'END { if ($0=="") print "New line found."; else print "No new line found." }' input_file

I created 2 files one with new line character and other with no new line charcter. For both these files, it still gives the following message:

New line found.

Please help.

What do you mean with newline character? A "\n"? An empty line?

What's the format of your file (dos/unix)? On which OS and shell?

1. The file is on a Unix OS.

2. Unix Hardware configuration:
Sun Microsystems Inc. SunOS 5.9

3. I need to search for end of line character i.e. /n on the last line of this file.

Please let me know if you will need more information.

Uhm... A bit complex but it should work:

Code:

tail -1 input_file | od -An -t oC -w1 | tail -1 | grep -c "012"

Returns 1 if newline found, otherwise 0.

2 problems:
a. when the command is executed it specifies "usage" in the result and
b. Looks like it retruns a value '0' for both types of files.

Please see below:

sma2z@ianb1as1 [/apps/prodcopy/export/RW10X] $ --> tail -1 Alert_enuCPU18.0002.exp | od -An -t oC -w1 | tail -1 | grep -c "012"
usage: od [-bcCdDfFoOsSvxX] [-] [file] [offset_string]
od [-bcCdDfFoOsSvxX] [-t type_string]... [-A address_base] [-j skip] [-N
count] [-] [file...]
0

sma2z@ianb1as1 [/apps/prodcopy/export/RW10X] $ --> tail -1 Alert_enuCPU16.0001.exp | od -An -t oC -w1 | tail -1 | grep -c "012"
usage: od [-bcCdDfFoOsSvxX] [-] [file] [offset_string]
od [-bcCdDfFoOsSvxX] [-t type_string]... [-A address_base] [-j skip] [-N
count] [-] [file...]
0


Thanks for looking into my problem.