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IF statement failure

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# 1  
Old 03-31-2010
IF statement failure
Hi Guys,

i have a variable which hold a string value of "in" when i try to compare this value against another value the if statement is not working.

Code:
$a=in
 
if [ "$a" == "=" ]
then
    echo "Not a Walid match"
else 
    echo "Walid Match"
fi

Thank You.
Last edited by pludi; 03-31-2010 at 02:27 AM.. Reason: code tags, please...
# 2  
Old 03-31-2010
try this
if($a eq "=")
# 3  
Old 03-31-2010
tried the way u said ... still its not working error message : binary operator expected

code

Code:
if [ $a eq "=" ]; then echo "Not a walid match"; else echo "walid match"; fi

suppose if i change to

Code:
if [ $a == "=" ]; then echo "Not a walid match"; else echo "walid match"; fi

it works but the output is "Walid Match" where as my ouput should be "Not a walid Match"
Last edited by pludi; 03-31-2010 at 02:39 AM.. Reason: code tags, please...
# 4  
Old 03-31-2010
copy "=" to a variable
$b = "="
# 5  
Old 03-31-2010
Quote:
Originally Posted by nitinrp1
Code:
$a=in
 
if [ "$a" == "=" ]
then
    echo "Not a Walid match"
else 
    echo "Walid Match"
fi

The red '$' is your problem. Remove it, and it should work. To check for further errors, run (depending on your shell)
Code:
ksh -n your.script
bash -n your.script

Also, if you're assigning strings it's always a good idea to put quotes around them.
# 6  
Old 03-31-2010
Moderator,

that was a typo in my script ... the $ is not there in my script ... but still its not working and not giving me the excepted result ... pls help
# 7  
Old 03-31-2010
Your logic is reversed : you try if $a equal '=' then not valid match
Use '!=' (not equal) or reverse the statements
Code:
a=in
if [ "$a" != "=" ]
then
    echo "Not a Walid match"
else
    echo "Walid Match"
fi

That could also be written
Code:
a=in
[ "$a" = "=" ] && echo "Valid Match" || echo "Not a Valid match"
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