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Replace multiple positions in records which match crireria

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# 1  
Old 06-02-2017
Replace multiple positions in records which match crireria
I have a test file a.txt

Code:
001 123 456 789
002 This is just a
001 test data
003 file.

I want to clear columns 5 and 6 if the first 3 characters are 001 using awk.

I tried following but does not work. Any suggestions?

Code:
awk 'BEGIN{OFS=FS=""} {if (substr($0,1,3)=="123") $5=" "; $6=" ";  print $0}' a.txt

# 2  
Old 06-02-2017
You say 001 but in your code you have 123?
# 3  
Old 06-02-2017
It is type. It should be 001 in code
# 4  
Old 06-02-2017
Hello Soham,

Your Input_file doesn't have 5th and 6th column itself, so if your actual Input_file has it then following may help you in same.
Code:
awk '(substr($0,1,3)=="001"){$5=$6=""}1'   Input_file

If your Input_file doesn't have 5th and 6th fields and you meant to remove the last two columns 3rd and 4th then following may help you in same.
Code:
 awk '(substr($0,1,3)=="001"){$3=$4=""}1'   Input_file

Thanks,
R. Singh
# 5  
Old 06-02-2017
I meant position 5 and 6.

I tried your command. Unfortunately it gives error

Code:
awk: syntax error near line 1
awk: bailing out near line 1

# 6  
Old 06-02-2017
Quote:
Originally Posted by Soham
I meant position 5 and 6.

I tried your command. Unfortunately it gives error

Code:
awk: syntax error near line 1
awk: bailing out near line 1

if on Solaris, use nawk instead of awk.
# 7  
Old 06-02-2017
Yes, I tried nawk. Now it does not give error but not desired result. Columns do not become blank.I even tried to change columns 3 and 4 to 5 and 6.
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