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Bash Display First Friday of the next month


 
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Operating Systems Linux Bash Display First Friday of the next month
# 8  
Bash/Gnu Date version
Code:
offsets=(5 4 3 2 1 0 6)
year=2018
for month in {01..12}
do
   date +"%m/%d/%Y" --date "$year/$month/01 + ${offsets[$(date +%w --date ${year}/${month}/01)]} days"
done
01/05/2018
02/02/2018
03/02/2018
04/06/2018
05/04/2018
06/01/2018
07/06/2018
08/03/2018
09/07/2018
10/05/2018
11/02/2018
12/07/2018

Of course, the disadvantage of my solution is that you are running date twice.
Or:
Code:
starts=(6 5 4 3 2 1 7)
year=2018
for month in {01..12}
do
    dstart=$(date +%w --date "$year/$month/01")
    printf "%02d/%02d/%d\n" ${month#0} ${starts[$dstart]} $year
done

Andrew

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