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Bash Display First Friday of the next month

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Operating Systems Linux Bash Display First Friday of the next month
# 8  
Bash/Gnu Date version
offsets=(5 4 3 2 1 0 6)
for month in {01..12}
   date +"%m/%d/%Y" --date "$year/$month/01 + ${offsets[$(date +%w --date ${year}/${month}/01)]} days"

Of course, the disadvantage of my solution is that you are running date twice.
starts=(6 5 4 3 2 1 7)
for month in {01..12}
    dstart=$(date +%w --date "$year/$month/01")
    printf "%02d/%02d/%d\n" ${month#0} ${starts[$dstart]} $year


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