9 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi,
I need a ksh script to replace indirect directory references in an .ini file with a env variable using sed or awk.
The .ini file is for example as such:
A=..
B=../
C=../..
D=../../
E=../bin
F=../../bin
G=../../bin/xml
H=../../bin/xml/
Need to replace an instance of .. or... (2 Replies)
Discussion started by: andyatit
2 Replies
2. Shell Programming and Scripting
Hello,
I've spent hours this morning reading various past forum posts and documentation pages but I can't find exactly what I need.
I'm trying to call a variable with a variable in the name without having to make a third variable.
For example:
path=AB
legAB=50
leg$path
I want to... (8 Replies)
Discussion started by: DFr0st
8 Replies
3. Red Hat
Hi all,
Hereby wish to have your advise for below:
Main concept is
I intend to get current directory of my script file.
This script file will be copied to /etc/init.d.
A string in this copy will be replaced with current directory value.
Below is original script file:
... (6 Replies)
Discussion started by: cielle
6 Replies
4. Shell Programming and Scripting
I have a file with two columns of numbers (member IDs):
1 1
2 1
3 1
4 2
5 4
6 1
7 5
8 3
9 2
Think of column 1 as the referee and column 2 as the referrer.
Is there a good way to backtrack who referred who? I would like an output, for this example here to be:
1 1
2 1
3 1
4 2 1 (2 Replies)
Discussion started by: mdlloyd7
2 Replies
5. Shell Programming and Scripting
Hello,
is there a kind soul who can answer me, does the SH support double substitution known as indirect expansion similar to BASH? The syntax for bash is ${!var}.
For instance in bash I can write something like this:
VAR="value"
REF_VAR="VAR"
echo ${!REF_VAR}
and get the "value"... (1 Reply)
Discussion started by: dimentiy
1 Replies
6. Shell Programming and Scripting
Hi
I have variable A_B=alpha
also var1="A"
var2="B"
I want to retrieve the value alpha using var1 and var2 , somthing like
echo ${${var1}_${var2}} that works. Obviously this is receiving syntax
error (6 Replies)
Discussion started by: sumir
6 Replies
7. Shell Programming and Scripting
Hi all,
I have a variable say var1 (output from somewhere, which I can't change)which store something like this:
echo $var1
name=fred
age=25
address="123 abc"
password=pass1234
how can I make the variable $name, $age, $address and $password contain the info?
I mean do this in a... (1 Reply)
Discussion started by: freddy1228
1 Replies
8. Shell Programming and Scripting
The construct ${#parameter} returns the number of characters in the parameter and ${!parameter} specifies an indirect variable. My question is: How do I combine these two. What I want is ${#!parameter} but this gives an error.
Of course I can use:
dummy=${!parameter}
${#dummy}
but that's a... (0 Replies)
Discussion started by: gone_bush
0 Replies
9. UNIX for Advanced & Expert Users
Using bash, I'm trying to read a .properties file (name=value pairs), assigning an indirect variable reference for each line in the file.
The trick is that a property's value string may contain the name of a property that occurred earlier in the file, and I want the name of the 1st property to... (5 Replies)
Discussion started by: tkrussel
5 Replies