I'm not sure why you are starting another thread to discuss what seems to be the same issue, but apparently in this thread the data you're looking for is in the first field on lines in your data instead of the last field.
As has been said before, providing sample input data (in CODE tags), desired output from that sample input (in CODE tags), and a clear statement of what shell and operating system you're using (including version numbers) would make it much easier to help you.
Does the version of HP-UX you're using have a ksh93 utility? If so, what output do you get from running the command:
Code:
printf '%(%s %Y-%m-%d %H:%M:%S)T\n'
in that shell?
If you don't have a ksh93 utility, what do you get if you run that command when using ksh as your shell?
Note that your problem has absolutely nothing to do with awk; the errors you are getting are from the date utility.
printf: Error processing format
printf: Error processing format
printf: Error processing format
printf: Error processing format
printf: Error processing format
printf: Error processing format
SunOS -s 5.10 Generic_147440-04 sun4u sparc SUNW,SPARC-Enterprise
Hi,
In a folder, there are files. I have a script which reads the current date and subtract the modification date of each file.
How do I achieve this?
Regards,
Joe (2 Replies)
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
hi all..
i want 2 know how 2 find 7days past date from current date..
when i used set datetime = `date '+%m%d%y'` i got 060613..
i just want to know hw to get 053013..
i tried using date functions but couldnt get it :( i use c shell and there is no chance that i can change that ..... (3 Replies)
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
Hi all,
I am trying to execute the following command in a sun solaris machine and getting the error as below.
bash-2.03$ date -d "1 day ago" +%Y%m%d
date: illegal option -- d
bash-2.03$ uname -a
SunOS gtrd02 5.8 Generic_117350-55 sun4u sparc SUNW,Sun-Fire-V440
Can anybody help me to... (1 Reply)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi All,
Is it possible to run date -d option in Solaris?
Do we have a work around so that -d option will be recognized
by solaris as it is recognized by linux.
I need this since i am using this in scripting and it works in Linux box. my problem is
it doesn't work in solaris box.
... (6 Replies)
hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
12-24-2018
