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find command to display size and date of a file


 
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Operating Systems HP-UX find command to display size and date of a file
# 1  
Question find command to display size and date of a file

Hi,

The blow code does not yeild any output.

Code:
 find . -name "*.jar" -o -name "*.ksh" -o -name "*.properties" -name "*.war" -o -name "*.ear" -o -name "*.sh" -o -name "*.cfg" -exec ls -l {} \;

I wish to print the filename filesize filedate in HP-UX.

Can anyone help ?
# 2  
try this

Code:
ls -lrt .jar* | awk '{print $9,$5,$6,$7,$8}

Here $9 is filesize, $5 is filesize and $6,7,8 is filedate
# 3  
Question

Quote:
Originally Posted by NareshN
try this

Code:
ls -lrt .jar* | awk '{print $9,$5,$6,$7,$8}

Here $9 is filesize, $5 is filesize and $6,7,8 is filedate
I need
Code:
find

command as I am checking under sub directories as well.
# 4  
Instead of -exec ls -l {} \; try using -ls
# 5  
Add below awk part...

Quote:
Originally Posted by mohtashims
Code:
 find . -name "*.jar" -o -name "*.ksh" -o -name "*.properties" -name "*.war" -o -name "*.ear" -o -name "*.sh" -o -name "*.cfg" -exec ls -l {} \; |   awk '{ print $NF, $5, $6,$7,$8}'

Can anyone help ?
# 6  
Quote:
Originally Posted by Ygor
Instead of -exec ls -l {} \; try using -ls

I tried these but both of them failed.

Code:
 
==> find . -name "*.jar" -o -name "*.ksh" -o -name "*.properties" -name "*.war" -o -name "*.ear" -o -name "*.sh" -o -name "*.cfg" -ls
find: bad option -ls
shp051a1:/appl/bea/deployments>
==> find . -name "*.jar" -o -name "*.ksh" -o -name "*.properties" -name "*.war" -o -name "*.ear" -o -name "*.sh" -o -name "*.cfg" ls
find: missing conjunction

# 7  
Perhaps try using brackets....
Code:
find . \( -name "*.jar" -o -name "*.ksh" -o -name "*.properties" -name "*.war" -o -name "*.ear" -o -name "*.sh" -o -name "*.cfg" \) -print | while read f; do ls -l "$f"; done


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