How to get defined precision after arithmetic operation using syncsort?


 
Thread Tools Search this Thread
Contact Us Post Here to Contact Site Administrators and Moderators How to Post in the The UNIX and Linux Forums How to get defined precision after arithmetic operation using syncsort?
# 1  
Old 03-16-2018
Lightbulb How to get defined precision after arithmetic operation using syncsort?

I have to do some arithmetic operation on Field 8 which is calculated by Field 9/Field 7

Suppose i have data like :
Code:
0800123456|JAN|2017|JAN|2018|0800123456|0|0.0000|0.00|
0800234567|JAN|2017|JAN|2018|0800234567|4|2.5812|10.32|
0800666666|JAN|2017|JAN|2018|0800666666|2|1.7255|3.45|
0800111111|DEC|2015|DEC|2018|0800111111|2|1.8312|7.32|
0800123456|JAN|2017|JAN|2018|0800123456|0|0.0000|0.00|
0800234567|JAN|2017|JAN|2018|0800234567|4|2.5812|10.32|
0800111111|DEC|2015|DEC|2018|0800111111|4|1.8312|7.32|

I used following code :
Code:
syncsort << endofsort
/INFILE $IN_FILE "|"

/fields
P_NUMBER 1:-1: en,
B_MONTH 2:-2:,
B_YEAR 3:-3: en,
D_MONTH 4:-4:,
D_YEAR 5:-5: en,
C_NUMBER 6:-6: en,
CALL_MINS 7:-7: en,
PRICE_PER_UNIT 8:-8: en,
AMOUNT 9:-9: en,

/CONDITION UNIT_PRICE_ZERO CALL_MINS = 0

/KEYS P_NUMBER ascending,B_MONTH ascending, B_YEAR ascending, D_MONTH ascending,D_YEAR ascending,C_NUMBER ascending

/SUMMARIZE
TOTAL CALL_COUNT,
TOTAL CALL_MINS,
TOTAL AMOUNT,

/DERIVEDFIELD NEW_PRICE_PER_UNIT
IF UNIT_PRICE_ZERO then PRICE_PER_UNIT
ELSE AMOUNT/CALL_MINS en 20 10/4 COMPRESS

/DERIVEDFIELD DEL "|"

/OUTFILE $OUT_FILE OVERWRITE

/REFORMAT
P_NUMBER,B_MONTH,B_YEAR,D_MONTH,D_YEAR,C_NUMBER,CALL_MINS,PRICE_PER_UNIT,DEL,AMOUNT

/STATISTICS /* Sends SyncSort */
/END
endofsort

Here i want to maintain 4 precision of unit price field.
COMPRESS is used to compress extra spaces but it also compress zeros of precision.

Can anyone suggest how to get required output.

Last edited by MadeInGermany; 03-16-2018 at 04:11 AM.. Reason: added code tags
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Using awk to do arithmetic operation

Hi, I've this following text file FileVersion = 1.03 Filetype = meteo_on_curvilinear_grid TIME = 0 hours since 2016-10-03 12:00:00 +00:00 -6.855 -6.828 -6.801 -6.774 -6.747 -6.719 -6.691 -6.663 -6.634 -6.606 -6.577 -6.548 -6.519 -6.489 TIME = 0 hours since... (2 Replies)
Discussion started by: xisan
2 Replies

2. Shell Programming and Scripting

Arithmetic operation in variable

Hi, Here is the script i try to perform arithmetic operation in two variables . git branch -r | while read brname ; do REV_COMMITS=`git rev-list --count $brname` echo "$brname has $REV_COMMITS" (( TOTAL = TOTAL + REV_COMMITS )) echo "in loop" $TOTAL done echo "total is " $TOTAL ... (3 Replies)
Discussion started by: greet_sed
3 Replies

3. UNIX for Dummies Questions & Answers

Basic arithmetic operation with awk?

input: Name|Operation rec_10|1+2+2- Output: rec_10|1 Basically I am trying to calculate the result of "the path" in $3 where the operators follow the number and not preceding them like we normally do: rec_10: +1+2-2=1 But I realise (I am sure there is a good reason for that) that awk... (7 Replies)
Discussion started by: beca123456
7 Replies

4. Shell Programming and Scripting

floating point arithmetic operation error

I am writing a script in zsh shell, it fetchs a number from a file using the awk command, store it as a variable, which in my case is a small number 0.62000. I want to change this number by multiplying it by 1000 to become 620.0 using the command in the script var2=$((var1*1000)) trouble is... (2 Replies)
Discussion started by: piynik
2 Replies

5. Shell Programming and Scripting

Arithmetic operation between columns using loop variable

Hi I have a file with 3 columns. say, infile: 1 50 68 34 3 23 23 4 56 ------- ------- I want to generate n files from this file using a loop so that 1st column in output file is (column1 of infile/(2*n+2.561)) I am doing like this: for ((i=1; i<=3; i++)) do a=`echo... (3 Replies)
Discussion started by: Surabhi_so_mh
3 Replies

6. Shell Programming and Scripting

Arithmetic operation with awk

I have output like following in a file usmtnz-dinfsi19 72 71 38 1199 1199 0.8 19:23:58 usmtnz-dinfsi19 72 71 38 1199 1199 0.8 19:24:04 (9 Replies)
Discussion started by: fugitive
9 Replies

7. Shell Programming and Scripting

How to perform arithmetic operation on date

Hi all, I would appreciate if anyone knows how to perform adding to date. As for normal date, i can easily plus with any number. But when it comes to month end say for example 28 Jun, i need to perform a plus with number 3, it will not return 1 Jul. Thanks in advance for your help. (4 Replies)
Discussion started by: agathaeleanor
4 Replies

8. UNIX for Dummies Questions & Answers

arithmetic operation on two columns

Hi, All, I have a file, its content is as follows: 100 150 120 135 140 170 I want to insert a column, its content is determined by the difference between the two values in the same line, if the difference is less than 20, the new value is 1, otherwise is 0. after the operation, the... (1 Reply)
Discussion started by: Jenny.palmy
1 Replies

9. Shell Programming and Scripting

Help with arithmetic operation

I am using egrep to extract numbers from a file and storing them as variables in a script. But I am not able to do any arithmetic operations on the variables using "expr" because it stores them as char and not integers. Here is my code and the error I get. Any help will be appreciated. #!/bin/sh... (3 Replies)
Discussion started by: emjayshaikh
3 Replies

10. Shell Programming and Scripting

Simple arithmetic operation

I have no idea why I can't get this to work, if anybody can help i would appreciate it. #!/bin/bash x=`cat counter.txt | wc -l` y= '$x / 7' printf "%d People have visited this page" $y :confused: (2 Replies)
Discussion started by: paladyn_2002
2 Replies
Login or Register to Ask a Question