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IP Range Assigning

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Old Unix and Linux 05-31-2016   -   Original Discussion by TryllZ
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OK, not getting it, so I will try and ask in a different way.

First, which octet changes in a an IP subnet range, the network octet or the host octet ?
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Old Unix and Linux 06-01-2016   -   Original Discussion by TryllZ
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What's your definition of an "octet"?

If its an 8-bit-byte: again, forget the octet. As you can see in your request, subnets can be defined by the bit like your teachers do with /18 and /22. Then, within the subnet definition, the network part is just counted up one by one to skim through the subnets.
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Old Unix and Linux 06-01-2016   -   Original Discussion by TryllZ
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Just wanted to understand this, is it safe to say that the second subnet starts after the broadcast address:

192.168.0.0 /22
255.255.252.0
192.168.0.0 – 192.168.(3).255(Broadcast address)
192.168.(4).0 – 192.168.(7).255(Broadcast address), then next subnet
192.168.(8).0 – 192.168.(11).255(Broadcast address), then next subnet
192.168.(12).0 – 192.168.(15).255(Broadcast address)
And so on...

Similarly for the below IP:

IP Address – 172.59.0.0
Custom Subnet Mask – 255.255.252.0
Broadcast Address – 172.59.3.255

172.59.0.0 - 172.59.3.255
172.59.4.0 - 172.59.7.255
172.59.8.0 - 172.59.11.255
172.59.12.0 - 172.59.15.255
And so on....
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Old Unix and Linux 06-01-2016   -   Original Discussion by TryllZ
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Yes. The broadcast address (or all-ones address) is the last in the range by definition.
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