Case Statement

 
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# 1  
Old 04-23-2012
Case Statement

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1. The problem statement, all variables and given/known data:
Hey, guys I really need some help with a project.

"Write a shell program that examines the command line arguments, counts and collects the number of options. Basically it has to collect and count the arguments that start with a "-" and the one's that don't start with a -

I know I have to use -*) and *) I am having trouble actually creating the structure


2. Relevant commands, code, scripts, algorithms:



3. The attempts at a solution (include all code and scripts):

I tried using some commands but I am not sure how case statement works


4. Complete Name of School (University), City (State), Country, Name of Professor, and Course Number (Link to Course):

SAC, San Antonio, TX Baker Unix

Note: Without school/professor/course information, you will be banned if you post here! You must complete the entire template (not just parts of it).
# 2  
Old 04-23-2012
Hi, have a look at getopts
# 3  
Old 04-23-2012
Please mention what Shell you are using.
# 4  
Old 04-23-2012
from bash's "help case": case WORD in [PATTERN [| PATTERN]...) COMMANDS ;;]... esac

So your starting point:
Code:
    case "$1" in
        -*) command;;
        *) command;;
    esac

You will want to look at shift and while so that you can loop across all command line arguments passed to the shell.
# 5  
Old 04-24-2012
Yes, I am using bash.

I've try using commands and it tells me it dosen't exist or i can't find that command what might I be doing wrong or do I have to structure that command in a specific way.
# 6  
Old 04-24-2012
show us. copy and paste what you try and what it does
# 7  
Old 04-24-2012
Code:
case "$1" in
-*) echo "Total of is $#";;
echo " Collected $@";;
*) echo "Total of non- is $#";;
echo "Collected $@";;
esac


I am not sure if this is even right but I know $# displays the total number of arguments and $@ shows the actual arguments but my results are that is showing all of them even for -*) still shows the ones without the -.

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