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# 1  
Old 03-16-2012
Cut | command line args

Hi,

Can you please hint me how to achieve the below?

Input:
$./script.sh start 1 2

Internally inside the script i want to set a single variable with $2 and $3 value?

Output:

CMD=$1
ARGS=$2 $3

--VInodh
# 2  
Old 03-16-2012
Code:
 
$ ./test.sh start 1 2 
CMD is : start
ARGS is : 1 2

 
$ cat test.sh
CMD=$1
ARGS="$2 $3"
echo "CMD is : $CMD"
echo "ARGS is : $ARGS"

# 3  
Old 03-16-2012
Forgot to mention. Small change..

The first argument is fixed, but remaining no . of args may be incremental.

I mean, I want all the args $2 ...$n to be assigned to variable.
# 4  
Old 03-16-2012
Code:
#! /bin/bash

CMD=$1
ARGS=${*:2:4}

echo $CMD
echo $ARGS

Code:
$ ./test.sh a b c d e f
a
b c d e

# 5  
Old 03-16-2012
Code:
 
#!/bin/bash
count=0
for i in `echo $@`
do
[ "$count" != "0" ] && ARGS="$ARGS $i"
count=1
done
echo $ARGS

This User Gave Thanks to itkamaraj For This Post:
# 6  
Old 03-16-2012
@itkamaraj: works fine.

@balajesuri: Thanks for reply. But your solution restricted to 4 args, but it doesnt handle for n args.


Thanks for the both.

-VInodh
# 7  
Old 03-16-2012
You should've been clear with the requirements. When you say from $2 to $n, it could mean from 2nd param to 6th param out of 10 params, right?

Code:
#! /bin/bash
CMD=$1
shift
ARGS=$*
echo $ARGS

This User Gave Thanks to balajesuri For This Post:
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