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Grep a pattern and print following n lines

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Operating Systems AIX Grep a pattern and print following n lines
# 1  
Old 02-05-2015
Grep a pattern and print following n lines
Hi all,

I am struck with the below requirement. I need to grep a particular pattern in a file and then print next n lines of it for further processing.
I have used the below code
Code:
grep -A 3 "pattern" filename

But it is throwing error as below.
Code:
grep: illegal option -- A

Can anyone help me with some alternates for this.

Thanks.
# 2  
Old 02-05-2015
That's an option to GNU grep, which not all systems have. What is your system?

Anyway, this should do:

Code:
awk 'PAT ~ $0 { N=LINES } (N--) > 0' LINES=5 PAT="qwerty" inputfile

Use nawk on Solaris.
# 3  
Old 02-05-2015
Hi Corona,
Thanks for the reply. My system is Solaris . But i need this for AIX too
I am getting error when used with awk and no output when used with nawk as below

Code:
$ awk 'PAT ~ $0 { N=LINES } (N--) > 0' LINES=5 PAT="ISEND" sqloutput1.log
awk: syntax error near line 1
awk: bailing out near line 1
$ nawk 'PAT ~ $0 { N=LINES } (N--) > 0' LINES=5 PAT="ISEND" sqloutput1.log
$

# 4  
Old 02-05-2015
Hello ssk250,

Could you please use /usr/xpg4/bin/awk, and /usr/xpg6/bin/awk in place of awk this should work.

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
ssk250
# 5  
Old 02-05-2015
Sorry, there was a mistake in my code.

Code:
awk '$0 ~ PAT { N=LINES } (N--) > 0' LINES=5 PAT="ISEND" sqloutput1.log

This User Gave Thanks to Corona688 For This Post:
ssk250
# 6  
Old 02-05-2015
(N--) > 0 can overflow with large files. Better (N && N--)!
This User Gave Thanks to MadeInGermany For This Post:
ssk250
# 7  
Old 02-06-2015
Hi All,

Thanks All. The below script worked for me

Code:
/usr/xpg4/bin/awk '$0 ~ PAT { N=LINES } (N--) > 0' LINES=5 PAT="ISEND" sqloutput1.log

Just want to know... In a similar way how the lines before this pattern can be printed.
Last edited by ssk250; 02-06-2015 at 12:37 AM.. Reason: Need to add another point
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