AIX

#!/usr/bin/ksh
#set -x

#Try this script.
#It will check and lock the accounts automatically for those logins that
#have not been used to s set number of days.

expdays=60 #<< ---- Set number of days in past here!
let expiry=86400*$expdays
locked=" "
LOG_FILE=/tmp/${0}.log
tmp1=/tmp/exp.tmp1.$$
tmp2=/tmp/exp.tmp2.$$
tmp2a=/tmp/exp.tmp2a.$$
tmp3=/tmp/exp.tmp3.$$

# List all users that are allowed to login
lsuser -a login account_locked time_last_login ALL |grep -Ev ^"root|daemon|bin|sys|adm|nobody" | grep "login=true" > $tmp1

# get all users who have logged in at least once with login date
grep 'time_last_login' $tmp1 | sed -e 's/login=true //' -e 's/account_locked=//' -e 's/time_last_login=//' >$tmp2

# get all users who have not logged in since creation
grep -v 'time_last_login' $tmp1 | sed -e 's/login=true //' -e 's/account_locked=//' >$tmp2a

# get today's date in seconds from epoch for comparison
year=`date +%Y`
day=`date +%j`
hour=`date +%H`
minute=`date +%M`

let today="($year - 1970) * 365 * 86400 + ($day - 1) * 86400 + $hour * 3600 + $minute * 60 + ($year - 1969) / 4 * 86400"

# for each user found, check whether has not been unused too long
cat $tmp2 |while read user locked last; do
     let min=$today-$expiry
     if [[ $min -gt $last ]]; then
          let login="($today - $last) / 86400"
          echo $user':'$login':'$locked >> $LOG_FILE
          #chuser shell='/usr/local/bin/locked' account_locked='true' $user
fi
done

# Remove the tmp files
rm $tmp1
rm $tmp2
rm $tmp2a

awk -v now="$(perl -e "print time")" '
   BEGIN{
      d=41
      el=now-(d*86400)
   }
   /:$/ {sub(/:/,""); a=$1; next}
   /time_last_login/ && !/^\*/ {if($3 < el) {print a}}
' lastlog