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Full Discussion: Simple cron job won't work
Top Forums UNIX for Dummies Questions & Answers Simple cron job won't work Post 46555 by joneja on Monday 19th of January 2004 04:04:24 PM
Old 01-19-2004
^M chars should be the cause.
You can remove them by opening the file in vi editor and using the foll command in the command mode:

%s/ctrl-v ctrl-m//g
(finally, it should show :%s/^M//g)
 

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readkey(3alleg4)                                                  Allegro manual                                                  readkey(3alleg4)

NAME
readkey - Returns the next character from the keyboard buffer. Allegro game programming library. SYNOPSIS
#include <allegro.h> int readkey(); DESCRIPTION
Returns the next character from the keyboard buffer, in ASCII format. If the buffer is empty, it waits until a key is pressed. You can see if there are queued keypresses with keypressed(). The low byte of the return value contains the ASCII code of the key, and the high byte the scancode. The scancode remains the same whatever the state of the shift, ctrl and alt keys, while the ASCII code is affected by shift and ctrl in the normal way (shift changes case, ctrl+letter gives the position of that letter in the alphabet, eg. ctrl+A = 1, ctrl+B = 2, etc). Pressing alt+key returns only the scan- code, with a zero ASCII code in the low byte. For example: int val; ... val = readkey(); if ((val & 0xff) == 'd') /* by ASCII code */ allegro_message("You pressed 'd' "); if ((val >> 8) == KEY_SPACE) /* by scancode */ allegro_message("You pressed Space "); if ((val & 0xff) == 3) /* ctrl+letter */ allegro_message("You pressed Control+C "); if (val == (KEY_X << 8)) /* alt+letter */ allegro_message("You pressed Alt+X "); This function cannot return character values greater than 255. If you need to read Unicode input, use ureadkey() instead. SEE ALSO
install_keyboard(3alleg4), ureadkey(3alleg4), keypressed(3alleg4), clear_keybuf(3alleg4), simulate_keypress(3alleg4) Allegro version 4.4.2 readkey(3alleg4)
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