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Top Forums UNIX for Beginners Questions & Answers awk regex woth text in each line Post 303046349 by cmccabe on Friday 1st of May 2020 03:03:52 PM
Old 05-01-2020
awk regex woth text in each line

The awk regex below produces the current,where
only the matching line are printed. However, I am trying to print all lines in test.txt,
and if the line matches the first regex the word "good" is printed after the line.
If the line does matches the second regex the word "test" is printed after the line.
If the line does not match the regex the word "bad" is printed after the line.
I'm not sure the best way to accomplish the desired but the logic is:

regex1
Code:
1. ensure each line begins with 00-0000
 2. followed by -some number
3. followed by -case insensitive male or female-BBB_xxx
 4. string of all Caps_

regex 2
Code:
1. starts with ani digits
 2. followed by - case insensitive test_

test.txt
Code:
00-0000-1234-Male-BBB_xxx.txt
11-1111_xxx.txt
00-0000-12345-female-BBB_xxx.txt
000000-Test_xxx.txt

Code:
awk '/^[0-9][0-9]-[0-9][0-9][0-9][0-9]-[[:digit:]]+-[Mm]ale|[Ff]emale-[A-Z]_*/' test.txt && awk '/^[[:digit:]]+-[Tt]est_*/'test.txt

current
Code:
00-0000-1234-Male-BBB_xxx.txt
00-0000-12345-female-BBB_xxx.txt
000000-Test_xxx.txt

desired
Code:
00-0000-1234-Male-BBB_xxx.txt    good
11-1111_xxx.txt    bad
00-0000-12345-female-BBB_xxx.txt    good
000000-Test_xxx.txt    test


Last edited by cmccabe; 05-01-2020 at 05:05 PM.. Reason: fixed format
 
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