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Top Forums Shell Programming and Scripting Custom exit message according to flag Post 303045146 by sea on Thursday 12th of March 2020 02:54:12 PM
Old 03-12-2020
You're welcome.

Originally Posted by da1
One question though regarding the following piece of code:
[[ 0 = $ret ]] && \
	exit_msg="SUCCESS - $exit_msg" || \
	exit_msg="FAILURE - $exit_msg"

Why not do a proper if/else statement here?
It's shorter and i'm lazy.
Also it only 'contains' 1 task per situation, so this is enough.
However, if there are more lines to be made for each situation, i'd go with a proper if/else statement as well.

Originally Posted by da1
I did that because of the "set -u". What would be the right approach?
Ok, can you elabortate on that? Why is it wrong (?) to append a string to a variable?
If you want to check wether a variable exists (or has content) or not (empty) and DECIDE what to execute according to that, it's a bad choice to fill the variables anway.

One usualy uses this to make sure a REQUIRED variable gets it's DEFAULT or FALLBACK values, as in:

I have.. uhm.. misspelled.. my... uhm.. concern... in the previous post, because:
${1:-} doesnt actualy do something, and is basicly the same as ${1}, but it (the first one) indicates that you wanted to put some variable there, which then might interfere.
Also, by setting a string to an empty variable, you'd say the script to ALWAYS use '$proxy', because '$proxy' would contain something. (well, not in your actual code, that's just bad syntax)

The set -u only requires you to declare the variable before invoking it.
So any of these are valid options for that case/command:
declare var
local var

--- Post updated at 21:54 ---

On a further note, your exit codes in those functions just exit the fuction, therefor return could be used there.

For example, try this:
my_msg(){ echo "${1:-some string i dont care} ; return 1 ; }
echo $ret
exit $ret

And then change the return number.

This User Gave Thanks to sea For This Post:

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