Top Forums Shell Programming and Scripting How do we display specific row of an output from bottom given line number? Post 303043989 by mohtashims on Wednesday 12th of February 2020 08:16:55 AM
If the user passes 1 then i need the newest latest file.

If the user passes 2 then i wish to display only the newest - 1 file i.e second latest file.

if the user passes 3 then the third latest file.

Code:
-bash-4.2$ ls -lt *.conf*
-rwxrwxrwx 1 user1 user 21627 Feb 11 17:17 httpd.conf_1581421731
-rwxrwxrwx 1 user1 user 15445 Feb 11 17:14 httpd-ssl.conf_1581421731
-rwxrwxrwx 1 user1 user 21624 Feb 11 17:13 httpd.conf_1581421456
-rwxrwxrwx 1 user1 user 15445 Feb 11 15:39 httpd-ssl.conf_1581421372
-rwxrwxrwx 1 user1 user 15445 Feb 11 15:39 httpd-ssl.conf_1581421456
-rwxrwxrwx 1 user1 user 21627 Feb 11 13:35 httpd.conf_1581408391
-rwxrwxrwx 1 user1 user 21627 Feb 11 13:35 httpd.conf_1581413246
-rwxrwxrwx 1 user1 user 21627 Feb 11 13:35 httpd.conf_1581415778
-rwxrwxrwx 1 user1 user 21627 Feb 11 13:35 httpd.conf_1581421372
-rwxrwxrwx 1 user1 user 21644 Feb 11 13:29 httpd.conf_1581408244
-rwxrwxrwx 1 user1 user 21644 Feb 11 13:29 httpd.conf_1581408293
-rwxrwxrwx 1 user1 user 21627 Feb 11 11:13 httpd.conf_1581399897
-rwxrwxrwx 1 user1 user 21627 Feb 11 11:13 httpd.conf_1581407966
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581399897
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581407966
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581408244
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581408293
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581408391
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581413246
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581415778
-bash-4.2$ ls -lt | sed -n "${1}p"
total 400
-rwxrwxrwx 1 user1 user 21627 Feb 11 17:17 httpd.conf_1581421731
-rwxrwxrwx 1 user1 user 15445 Feb 11 17:14 httpd-ssl.conf_1581421731
-rwxrwxrwx 1 user1 user 21624 Feb 11 17:13 httpd.conf_1581421456
-rwxrwxrwx 1 user1 user 15445 Feb 11 15:39 httpd-ssl.conf_1581421372
-rwxrwxrwx 1 user1 user 15445 Feb 11 15:39 httpd-ssl.conf_1581421456
-rwxrwxrwx 1 user1 user 21627 Feb 11 13:35 httpd.conf_1581408391
-rwxrwxrwx 1 user1 user 21627 Feb 11 13:35 httpd.conf_1581413246
-rwxrwxrwx 1 user1 user 21627 Feb 11 13:35 httpd.conf_1581415778
-rwxrwxrwx 1 user1 user 21627 Feb 11 13:35 httpd.conf_1581421372
-rwxrwxrwx 1 user1 user 21644 Feb 11 13:29 httpd.conf_1581408244
-rwxrwxrwx 1 user1 user 21644 Feb 11 13:29 httpd.conf_1581408293
-rwxrwxrwx 1 user1 user 21627 Feb 11 11:13 httpd.conf_1581399897
-rwxrwxrwx 1 user1 user 21627 Feb 11 11:13 httpd.conf_1581407966
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581399897
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581407966
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581408244
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581408293
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581408391
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581413246
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581415778


Thus if the user passes 3 then the below file should be be printed
Code:
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581408391

if the user passes 4 then the below file should be be printed
Code:
-rwxrwxrwx 1 user1 user 15445 Feb 11 11:12 httpd-ssl.conf_1581408293

@Rudic your suggestion does not help get my desired output. Kindly suggest.
 
Test Your Knowledge in Computers #907
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The Unix shell command line is a sequence of ASCII text words delimited by curly braces.
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