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Full Discussion: Insert year in ls -l command
Top Forums UNIX for Beginners Questions & Answers Insert year in ls -l command Post 303042711 by Aia on Friday 3rd of January 2020 08:06:51 PM
Old 01-03-2020
Quote:
Originally Posted by kumarinfa
@Jim,

Thanks for your reply, and yes i am well aware about DATE command and its relevant formats, kindly follow my first post carefully as i mentioned that i cannot use any ls options because i am getting file listing from ftp server. Is there any command which can give me desired result directly from ftp while using ls?

TIA

--- Post updated at 07:10 PM ---

Thank you @Ravinder,

I understood very well what you explained. Also can you tell me what if i have to extract year if i get input like this:

Code:
-rw-r--r-- 1 360 600 165923 Dec 31 11:29 12312019 file1_12312019_062449.csv

Here 2019 is not whole word rather part of second field, tried using substr but not able to get the idea that how to nest split and substr function.

TIA
Code:
perl -ple 's/\w+?(\d{4})[._]/$1 $&/' kumarinfa.file

Output:
Code:
-rw-r--r--    1 360      600         94255 Jan 01 11:16  2020 file1_2020.csv
-rw-r--r--    1 360      600        114573 Dec 29 11:10  2019 file2_2019.csv
-rw-r--r--    1 360      600         41006 Dec 30 11:09  2019 file3_2019.csv
-rw-r--r--    1 360      600        165923 Dec 31 11:29  2019 file4_2019.csv
-rw-r--r-- 1 360 600 165923 Dec 31 11:29  2019 file1_12312019_062449.csv

Code:
awk '
{
  split($NF,array,"[_.]")
  yyyy = substr(array[2], length(array[2])-3)
  $NF=yyyy OFS $NF
}1' kumarinfa.file
-rw-r--r-- 1 360 600 94255 Jan 01 11:16 2020 file1_2020.csv
-rw-r--r-- 1 360 600 114573 Dec 29 11:10 2019 file2_2019.csv
-rw-r--r-- 1 360 600 41006 Dec 30 11:09 2019 file3_2019.csv
-rw-r--r-- 1 360 600 165923 Dec 31 11:29 2019 file4_2019.csv
-rw-r--r-- 1 360 600 165923 Dec 31 11:29 2019 file1_12312019_062449.csv

 

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LEARN ABOUT SUNOS

cal

cal(1)								   User Commands							    cal(1)

NAME

       cal - display a calendar

SYNOPSIS

       cal [ [month] year]

DESCRIPTION

       The  cal  utility writes a Gregorian calendar to standard output. If the year operand is specified, a calendar for that year is written. If
       no operands are specified, a calendar for the current month is written.

OPERANDS

       The following operands are supported:

       month	Specify the month to be displayed, represented as a decimal integer from 1 (January) to 12 (December). The default is the  current
		month.

       year	Specify  the year for which the calendar is displayed, represented as a decimal integer from 1 to 9999. The default is the current
		year.

ENVIRONMENT VARIABLES

       See  environ(5) for descriptions of the following environment variables that affect the execution of cal: LANG, LC_ALL, LC_CTYPE,  LC_TIME,
       LC_MESSAGES, and NLSPATH.

       TZ	Determine the timezone used to calculate the value of the current month.

EXIT STATUS

       The following exit values are returned:

       0	Successful completion.

       >0	An error occurred.

ATTRIBUTES

       See attributes(5) for descriptions of the following attributes:

       +-----------------------------+-----------------------------+
       |      ATTRIBUTE TYPE	     |	    ATTRIBUTE VALUE	   |
       +-----------------------------+-----------------------------+
       |Availability		     |SUNWesu			   |
       +-----------------------------+-----------------------------+
       |Interface Stability	     |Standard			   |
       +-----------------------------+-----------------------------+

SEE ALSO

       calendar(1), attributes(5), environ(5), standards(5)

NOTES

       An  unusual calendar is printed for September 1752. That is the month 11 days were skipped to make up for lack of leap year adjustments. To
       see this calendar, type:

       cal 9 1752

       The command cal 83 refers to the year 83, not 1983.

       The year is always considered to start in January.

SunOS 5.10							    1 Feb 1995								    cal(1)
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