Sponsored Content
Full Discussion: Insert year in ls -l command
Top Forums UNIX for Beginners Questions & Answers Insert year in ls -l command Post 303042667 by RavinderSingh13 on Thursday 2nd of January 2020 10:07:24 PM
Old 01-02-2020
Quote:
Originally Posted by kumarinfa
@Ravindersingh13
Thank you for your suggestion, Yes i have save my output of ls command in file. and Can you please explain little bit in detail what we are doing in this solution.
Also what if my input is:
Code:
-rw-r--r-- 1 360 600 165923 Dec 31 11:29 12312019 file1_12312019_062449.csv

How can i extract year part in same solution, tried but could not get the expceted.
Thank you again
Hello kumarinfa,

Following is the complete explanation.

Code:
awk '                               ##starting awk program from here.
{
  split($NF,array,"[_.]")           ##Using split to splitting the last field of current line into an array named array with field separator of underscore and dot.
  $NF=array[2] OFS $NF              ##resetting last field value with 2nd value of array(which was year value) OFS and last field value itself.
}
1                                   ##Mentioning 1 will print edited/non-edited lines here. 
' Input_file                        ##Mentioning Input_file name here.

Thanks,
R. Singh

Last edited by RavinderSingh13; 01-02-2020 at 11:40 PM..
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

listing year in ls command

Hi all .. As per rule i searched the forum i am not able found out ... I want to display the year in when listing the files .. when i use ls -lt it is not displaying files with recent 6 month old .. I know that perderabo has written a script for that if you give that link it will be... (3 Replies)
Discussion started by: arunkumar_mca
3 Replies

2. Shell Programming and Scripting

Printing Year in ls -ltr command

Hi, When retrieving parameters of a file using ls command i need to print the year part . When i do ls -ltr the following output is displayed -rwxrwxrwx 1 d_infd d_infd 1711 Jan 8 2004 wf1.class. Here the year part is not displayed only Jan 8 is displayed. Can any one... (9 Replies)
Discussion started by: ragugct
9 Replies

3. Shell Programming and Scripting

Last Command not giving year

Hi All, i want the last login details along with year. i tried below command but not giving me the year of last login. last <$Userid> | head -1 i heard that if it is current year then it wont display the year else it will display the year. is it so? if yes then , is there any way of... (1 Reply)
Discussion started by: ani_rvce
1 Replies

4. UNIX for Dummies Questions & Answers

Last Command not giving year

Hi All, i want the last login details along with year. i tried below command but not giving me the year of last login. last <$Userid> | head -1 i heard that if it is current year then it wont display the year else it will display the year. is it so? if yes then , is there any way of... (1 Reply)
Discussion started by: ani_rvce
1 Replies

5. UNIX for Dummies Questions & Answers

sed insert command and variable expansion/command substitution

I know this script is crummy, but I was just messing around.. how do I get sed's insert command to allow variable expansion to show the filename? #!/bin/bash filename=`echo $0` /usr/bin/sed '/#include/ { i\ the filename is `$filename` }' $1 exit 0 (8 Replies)
Discussion started by: glev2005
8 Replies

6. Emergency UNIX and Linux Support

LAST command with Year

Hi Guys, I'm trying to identify the last logins by all the users in the system in AIX. the last command gives me the output, but there is no year displayed for it . Since there is a duplication of months i mean Apr 2010 and Apr 2009 also its giving me inaccurate data.. Is there a way I can filter... (4 Replies)
Discussion started by: kkeng808
4 Replies

7. UNIX for Advanced & Expert Users

unix command : how to insert text at the cursor location via command line?

Hi, Well my title isn't very clear I think. So to understand my goal: I have a script "test1" #!/bin/bash xvkbd -text blabla with xbindkeys, I bind F5 key in order it runs my test1 script So when I press F5, test1 runs. I'm under Emacs/Vi and I press F5 in order to have "blabla" be... (0 Replies)
Discussion started by: xib.be
0 Replies

8. Linux

uptime command output when the server is running more than one year?

What is the uptime command output when the server is running more than one year? My doubt is whether it show in number of days format or number years and number of days format? For example, Assume the server is running 400 days 3 hrs 3 min 3 secs. The output like 400 days 3:3 min or 1 year 5... (3 Replies)
Discussion started by: maruthu
3 Replies

9. UNIX for Dummies Questions & Answers

Unix man command to find out month of the year?

how can i display month of the year i was born with using man command? thanks (2 Replies)
Discussion started by: janetroop95
2 Replies

10. UNIX for Dummies Questions & Answers

Command to print previous year in UNIX

hi all, I use date +%Y which gives Current year. Requirement: I want previous year to be printed. Please help me. Note: I tried date +%d/%m/%Y -d "-1 years" which is not working. (10 Replies)
Discussion started by: wasim999
10 Replies
A2P(1)							 Perl Programmers Reference Guide						    A2P(1)

NAME
a2p - Awk to Perl translator SYNOPSIS
a2p [options] [filename] DESCRIPTION
A2p takes an awk script specified on the command line (or from standard input) and produces a comparable perl script on the standard output. OPTIONS Options include: -D<number> sets debugging flags. -F<character> tells a2p that this awk script is always invoked with this -F switch. -n<fieldlist> specifies the names of the input fields if input does not have to be split into an array. If you were translating an awk script that processes the password file, you might say: a2p -7 -nlogin.password.uid.gid.gcos.shell.home Any delimiter can be used to separate the field names. -<number> causes a2p to assume that input will always have that many fields. -o tells a2p to use old awk behavior. The only current differences are: o Old awk always has a line loop, even if there are no line actions, whereas new awk does not. o In old awk, sprintf is extremely greedy about its arguments. For example, given the statement print sprintf(some_args), extra_args; old awk considers extra_args to be arguments to "sprintf"; new awk considers them arguments to "print". "Considerations" A2p cannot do as good a job translating as a human would, but it usually does pretty well. There are some areas where you may want to examine the perl script produced and tweak it some. Here are some of them, in no particular order. There is an awk idiom of putting int() around a string expression to force numeric interpretation, even though the argument is always integer anyway. This is generally unneeded in perl, but a2p can't tell if the argument is always going to be integer, so it leaves it in. You may wish to remove it. Perl differentiates numeric comparison from string comparison. Awk has one operator for both that decides at run time which comparison to do. A2p does not try to do a complete job of awk emulation at this point. Instead it guesses which one you want. It's almost always right, but it can be spoofed. All such guesses are marked with the comment ""#???"". You should go through and check them. You might want to run at least once with the -w switch to perl, which will warn you if you use == where you should have used eq. Perl does not attempt to emulate the behavior of awk in which nonexistent array elements spring into existence simply by being referenced. If somehow you are relying on this mechanism to create null entries for a subsequent for...in, they won't be there in perl. If a2p makes a split line that assigns to a list of variables that looks like (Fld1, Fld2, Fld3...) you may want to rerun a2p using the -n option mentioned above. This will let you name the fields throughout the script. If it splits to an array instead, the script is probably referring to the number of fields somewhere. The exit statement in awk doesn't necessarily exit; it goes to the END block if there is one. Awk scripts that do contortions within the END block to bypass the block under such circumstances can be simplified by removing the conditional in the END block and just exiting directly from the perl script. Perl has two kinds of array, numerically-indexed and associative. Perl associative arrays are called "hashes". Awk arrays are usually translated to hashes, but if you happen to know that the index is always going to be numeric you could change the {...} to [...]. Iteration over a hash is done using the keys() function, but iteration over an array is NOT. You might need to modify any loop that iterates over such an array. Awk starts by assuming OFMT has the value %.6g. Perl starts by assuming its equivalent, $#, to have the value %.20g. You'll want to set $# explicitly if you use the default value of OFMT. Near the top of the line loop will be the split operation that is implicit in the awk script. There are times when you can move this down past some conditionals that test the entire record so that the split is not done as often. For aesthetic reasons you may wish to change index variables from being 1-based (awk style) to 0-based (Perl style). Be sure to change all operations the variable is involved in to match. Cute comments that say "# Here is a workaround because awk is dumb" are passed through unmodified. Awk scripts are often embedded in a shell script that pipes stuff into and out of awk. Often the shell script wrapper can be incorporated into the perl script, since perl can start up pipes into and out of itself, and can do other things that awk can't do by itself. Scripts that refer to the special variables RSTART and RLENGTH can often be simplified by referring to the variables $`, $& and $', as long as they are within the scope of the pattern match that sets them. The produced perl script may have subroutines defined to deal with awk's semantics regarding getline and print. Since a2p usually picks correctness over efficiency. it is almost always possible to rewrite such code to be more efficient by discarding the semantic sugar. For efficiency, you may wish to remove the keyword from any return statement that is the last statement executed in a subroutine. A2p catches the most common case, but doesn't analyze embedded blocks for subtler cases. ARGV[0] translates to $ARGV0, but ARGV[n] translates to $ARGV[$n-1]. A loop that tries to iterate over ARGV[0] won't find it. ENVIRONMENT
A2p uses no environment variables. AUTHOR
Larry Wall <larry@wall.org> FILES
SEE ALSO
perl The perl compiler/interpreter s2p sed to perl translator DIAGNOSTICS
BUGS
It would be possible to emulate awk's behavior in selecting string versus numeric operations at run time by inspection of the operands, but it would be gross and inefficient. Besides, a2p almost always guesses right. Storage for the awk syntax tree is currently static, and can run out. perl v5.18.2 2014-01-06 A2P(1)

Featured Tech Videos

All times are GMT -4. The time now is 06:50 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy