Did you try to cd into that directory as root for troubleshooting purposes?
Yes I did. It works fine that way.
Quote:
Originally Posted by hicksd8
Part of the pathname is "NAS". Can I assume that is Network Attached Storage"?? If so, what is that device??
Usually when working with NAS (especially Windows based NAS) the access rights that you get are the lesser of the NAS rights and the Unix/Linux rights. For example, Windows has a right to "list the contents" which, if set against you on the parent directory, will stop you entering the subdirectory.
So have you considered that the problem may not lay with the Linux system at all.
It is NFS. Would changing the sticky bit help? I tried 2770 but that did not help either.
On my FTP server (Darwin/Mac OS X -- pretty much FreeBSD), I need to apply the following permissions to a directory:
1. A specific owner with full access
2. A specific group with full access
3. A specific group with read-only access
4. No access whatsoever for everyone else
I understand... (5 Replies)
Hi,
A simple and silly question on Unix.
I have a directory named "a" and I would like to grant permission to group name "text" to access, read and execute my directory.
Could anyone help me?
Thanks. (2 Replies)
Hi,
Need awk help to group and print lines to format the output as shown below
INPUT FORMAT
set echo on
set heading on
set spool on
/* SCHEMA1 */ CREATE TABLE T1;
/* SCHEMA1 */ CREATE TABLE T2;
/* SCHEMA1 */ CREATE TABLE T3;
/* SCHEMA1 */ CREATE TABLE T4;
/* SCHEMA1 */ CREATE TABLE T5;... (5 Replies)
How can I write a script that determines the directory the user is in, and displays that path up until a particular point?
Specifically, I need to find the text "packages" in the directory name, then I need to capture that directory and the one below it.
For example, if the user is in the... (5 Replies)
i have a directory like this:
i want to get the subpaths:
/home/user/public_html/a/b
subpath= a/b
/home/user/public_html/a/b/c
subpath= a/b/c
i can get the user like
echo $fulldirectory |awk -F/ '{print $3}'
but im not sure how to get the rest of it after public_html
any ideas?... (3 Replies)
Hi,
In the following output you can see the the user "richard" is a member on the team/group "developers":
# id richard
uid=10247(richard) gid=100361(developers) groups=100361(developers),10053(testers)
but in the following details of the said group (developers), the said user... (3 Replies)
Discussion started by: indiansoil
3 Replies
LEARN ABOUT HPUX
create_directory
create directory(1m) create directory(1m)NAME
create directory - Creates a directory
SYNOPSIS
cdscp create directory directory-name [clearinghouse clearinghouse-name]
ARGUMENTS
The full name of the directory The name of the clearinghouse in which you create the directory.
DESCRIPTION
The create directory command creates a directory with the name that you specify. If you do not specify a clearinghouse, CDS creates the
master replica of the directory in the same clearinghouse as the new directory's parent directory.
Privilege Required
You must have the following permissions in order to create a directory: read and insert permission to the parent directory; write permis-
sion to the clearinghouse in which the master replica of the new directory is to be stored.
In addition, the server principal must have read and insert permission to the parent directory.
NOTES
To ensure that all replicas are consistent, perform an immediate skulk of the parent directory after issuing this command.
This command is replaced at Revision 1.1 by the dcecp command and may not be provided in future releases of DCE.
EXAMPLE
The following command creates a directory named /.:/sales. cdscp> create directory /.:/sales
RELATED INFORMATION
Commands: delete directory(1m), list directory(1m), set directory(1m), set directory to skulk(1m), show directory(1m)
create directory(1m)