Its my pleasure: let us first start with:

Code:

getline()
{
[...]
retcd=0
return $retcd;
exit $retcd
[...] 
}

These lines (the same construct is used several times) do not make any sense: return leaves the subroutine and branches back into the calling routine. So, whatever is after return, it will not be executed because execution never gets there. In this case this is lucky, by the way, because exit would leve the script completely and i doubt this is what you want.

Second:

Code:

retcd=0
return $retcd

what happens in the second line is: the shell notices that there is a variable (retcd) to expand and replaces the variables name with its content:

Code:

return 0

Only then the line is executed. You do NOT pass back a variable you pass back a variables content. Because the variable itself is local to the subroutine the calling routine will not know about the variable, therefore:

Code:

getline()
{
return $retcd;
}
getline
if [ "$retcd" = 0 ]

won't work because in the main part the variable "retcd" doesn't exist.

I haven't bothered to look for further logical errors because your script is so poorly formatted that it is hard to find out where (and if) the ifs and elses and fis all match. I suggest you reformat your code in your own interest, because this is nearly unreadable.

One more thing:

Code:

echo ${line} | egrep "Realm Server Startup sequence completed" > /dev/null 2>&1
if (( $? == 0 )); then

You obviously try to find out if a certain string contains another string. You can do that by simply:

Code:

if echo "${line}" | grep -q "Realm Server Startup sequence completed" 2>/dev/null ; then

First, you do not need egrep to search for a fixed string, second, you can use the command itself (and its return code) for if to process and lastly you do not need to redirect output when you can switch it off ("-q") before it even is produced.

I hope this helps.

bakunin