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Homework and Emergencies Homework & Coursework Questions Values rotation in array with bash Post 303035471 by Nexy on Saturday 25th of May 2019 10:16:03 AM
Old 05-25-2019
Quote:
Originally Posted by RudiC
You seem to have some logical errors in your script:
- mixing up array indices with array values (tmp being assigned a value but then used for an index).

- using a constant (2) when the shift span (n) is given.
- outputting the modified array twice instead of comparing the two before and after


How about
Code:
$ array=( $(seq 1 "$box"))
$ echo " Original array : " ${array[*]}
 Original array :  1 2 3 4 5 6 7 8 9 10
$ echo " shift:" $n
 shift: 4
$ array=( $(for ((i=n; i; i--)); do echo -n  ${array[-i]}" "; unset array[-i];  done; echo ${array[@]}) )
$ echo " array shifted : " ${array[*]}
 array shifted :  7 8 9 10 1 2 3 4 5 6

Quote:
Originally Posted by MadeInGermany
Comment on the previous solution: it allows echo ${array[-i]} because the =( ) splits on IFS i.e. space and newline.

If there is a cyclic shift, the % operator (modulo) is nice!
The following allows a very big (and even negative) shift:

Code:
...
# print array[ ] right-shifted by n
print_array_shifted(){
  local len=${#array[@]}
  local start=$((len-n))
  local end=$((start+len))
  local i
  for ((i=start; i<end; i++))
  do
    echo "${array[i%len]}"
  done
}

echo " Original array : ${array[*]}"
array=( $(print_array_shifted) )
echo " Array shifted : ${array[*]}"

Hello ! Smilie

Thank you for your help !!

For me, the only problem was this line :

Code:
unset array[-i]

So I had to replace this line by :

Code:
  Unset array[$(( ${#array[*]}-1))]

Now it works perfectly ! Thank you very much ! Smilie
 

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