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Top Forums UNIX for Beginners Questions & Answers How do I assign the output of a command to a variable within a loop in bash? Post 303033974 by Don Cragun on Monday 15th of April 2019 12:48:59 PM
Old 04-15-2019
Please show us your entire script instead of showing us one line at a time.

It seems highly likely that you are setting the variable you want inside a sub-shell and that makes the assigned value invisible outside of that sub-shell. But we can't know that until we can see all of your code.
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BASHBUG(1)						      General Commands Manual							BASHBUG(1)

NAME
bashbug - report a bug in bash SYNOPSIS
bashbug [--version] [--help] [email-address] DESCRIPTION
bashbug is a shell script to help the user compose and mail bug reports concerning bash in a standard format. bashbug invokes the editor specified by the environment variable EDITOR on a temporary copy of the bug report format outline. The user must fill in the appropriate fields and exit the editor. bashbug then mails the completed report to bug-bash@gnu.org, or email-address. If the report cannot be mailed, it is saved in the file dead.bashbug in the invoking user's home directory. The bug report format outline consists of several sections. The first section provides information about the machine, operating system, the bash version, and the compilation environment. The second section should be filled in with a description of the bug. The third sec- tion should be a description of how to reproduce the bug. The optional fourth section is for a proposed fix. Fixes are encouraged. ENVIRONMENT
bashbug will utilize the following environment variables if they exist: EDITOR Specifies the preferred editor. If EDITOR is not set, bashbug defaults to emacs. HOME Directory in which the failed bug report is saved if the mail fails. TMPDIR Directory in which to create temporary files and directories. SEE ALSO
bash(1) AUTHORS
Brian Fox, Free Software Foundation bfox@gnu.org Chet Ramey, Case Western Reserve University chet@po.cwru.edu GNU Bash-4.0 1998 July 30 BASHBUG(1)
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