I have a big, ugly query which is quadratic in the input size and therefore want to display an approximate completion time prior to sending it off:
Syntactically this is wrong and is merely illustrative. There is no FROM clause, so I cannot use a traditional subquery. How would this be programmed in MySQL 5.7?
Hi there,
I have a hierarchical database that include 4 tables. Table A is the parent of B, B is Parent of C, C is parent of D. If I want to query everything in D that is associated with A.name, how do I do that? Thanks!
YanYan (0 Replies)
Hi there, I have a table that stores multiple records for many different servers, each of which is timestamped ... I wanted to write a query that would enable me to only output the "latest" record (based on timestamp) for each "unique" server. So for example my main table looks like this
... (3 Replies)
hello all
i have 2 columns every column in the following format
column1
2011-04-01 11:39:54
column2
2019-02-03 00:00:00
i want get difference between above data as following
2 days 11:39
how to do so ?
i tried many functions but nothing works
please advice what is the query... (6 Replies)
Hi,
I want to access mysql query from database , for that i have tried the below code
#! /bin/bash
TABLE_NAME=database1
USER_NAME=root
IP_ADDR=111.20.9.256
somevar=`echo "select altid from alert where altid='2724'"| mysql -h $IP_ADDR -u $USER_NAME $TABLE_NAME `
echo $somevar
... (1 Reply)
Hi,
I want to run below query on shellscript but having one problm.
ADV=$( mysql -h "$IP_ADDR" -u "$USER_NAME" "$TABLE_NAME" -BNe" SELECT ADV FROM indata where inid='$INSTRUID' and Date='$latest Date';" )
here Date column contans different below dates
2011-12-01... (0 Replies)
Hi,
I want to run below query on shellscript but having one problm.
ADV=$( mysql -h "$IP_ADDR" -u "$USER_NAME" "$TABLE_NAME" -BNe" SELECT ADV FROM indata where inid='$INSTRUID' and Date='$latest Date';" )
here Date column contans different below dates
2011-12-01... (11 Replies)
Hello
i have created mysql query to compare to values and get difference in percentage
as following:
SELECT file_name, 100 - ((100 * (SELECT file_count FROM xipi_files z WHERE x.file_group = z.file_group AND x.file_name = z.file_name AND z.insert_date = CURDATE( ) - INTERVAL 1 DAY)) /... (1 Reply)
Hi All,
i have a table in mysql with the following data
Table name Test
Assettype Serial_No Status location
Mouse 123456 In Stock chennai
Mouse 98765 Allocated chennai
Keyboard ... (2 Replies)