I repeat: What operating system are you using? What version of sed are you using?
open VMS .. almost same to other other operating systems.
------ Post updated at 10:41 PM ------
sorry i said it wrong earlier. . i want sed to notify me for any violating record. that's the goal
------ Post updated at 10:43 PM ------
sorry for making a mistake in my original explaination , i corrected it .. i just want sed to output the violating records if any
------ Post updated at 10:55 PM ------
anotehr example to clear things up , from this file i want sed to output
because both of them do not have either 01,03,05,07,10,11 at 9th and 10th position ------ Post updated at 11:00 PM ------
i am stuck with production issue need help urgently .
Don you said finding 01,03,05,07,10,11 at 9th an 10th position in a string is easy .. can you give me sed command for it please?
------ Post updated at 11:08 PM ------
I tried Rudi's command on sun solaris, Linux . .also not working .
If you can give me this solution on solaris or Linux its also fine for me
------ Post updated at 11:47 PM ------
Quote:
Originally Posted by RudiC
In your regex, you want [ICODE
00[/ICODE] in positions 9 and 10. And, you may want to reread the regex documentation, as (man regex): So your bracket expr. seems to have too large a list, including 0 and , . On top, you are deleting the matching lines, so reverse the effect. Try instead:
or, for better readability
I tried your command on unix and its returning me the strings that have valid numbers at 9th and 10th position e.g "01","03","05","07","10","11" ,
I want only the three records from this file that have "33" ,"17" and "00" at 9th and 10th position.
operating system is sun solaris and Linux .
Moderator's Comments:
Please use CODE tags for data as well as required by forum rules!
Last edited by RudiC; 09-27-2018 at 04:38 AM..
Reason: Added CODE tags.
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