Regexes enclosed in slashes /.../ are regex constants, i.e. taken verbatim / literally. So a won't be replaced by its contents but matches "a".
Try to build the regex from partial string constants and variable contents, like e.g.
Code:
gsub("level=\"" a "\" n=\"[0-9]\"", "")
Not sure, though, what your intentions are with the square brackets around the a variable. And, why not a taylored regex (with "alternation") in lieu of the loop across a .
Some decent input (good and bad, i.e. to be matched or not) samples would help to understand what you're after.
This was the code needed to make it work! Thank you!
The big issue was that it must match perfectly or it would mess up the printout by going past its point and overwriting other data. With the forums help , I got that fixed (after 6hrs of droning at the comp). Maybe there is a very simple way, but none of the other offered solutions have worked so far, though I did learn new things from them.
The square brackets were just a beginners mistake; I was trying to use them as some sort way of inputting a substitution.
If anyone is interested, a working solution is here. It's not the most efficient, but it works perfectly. If anyone wants all the code, just ask:
Code:
# Find 'sense id' number and store in a variable
{ /<sense id=\"n.*" level/; {vID = substr($2, 1, length($2)-1)}}
# Used for testing to see value:
# {print "vID: " vID}
# If matched then print section divider
{ for (vid = 0; vid <= 19; vid++){
{ for (vl = 0; vl <= 3; vl++){
{ for (vn = 0; vn <=25; vn++){
{if (vn<=10) {vnx=vn } }
{if (vn==11) {vnx="I" } }
{if (vn==12) {vnx="II" } }
{if (vn==13) {vnx="III" } }
{if (vn==14) {vnx="IV" } }
{if (vn==15) {vnx="IV." } }
{if (vn==16) {vnx="V" } }
{if (vn==17) {vnx="V." } }
{if (vn==18) {vnx="A" } }
{if (vn==19) {vnx="B" } }
{if (vn==20) {vnx="C" } }
{if (vn==21) {vnx="D" } }
{if (vn==22) {vnx="E" } }
{if (vn==23) {vnx="F" } }
{if (vn==24) {vnx="G" } }
{if (vn==25) {vnx="H" } }
# Used for testing to see values:
# valuev="<sense " vID "." vid "\" level=\"" vl "\" n=\"" vnx "\" opt=\"n\">"; print valuev "\n"
# {gsub("<sense " vID "." vid "\" level=\"" vl "\" n=\"" vnx "\" opt=\"n\">", vdefSep)}
# Everything is ready, so try to make a match!
{gsub("<sense " vID "." vid "\" level=\"" vl "\" n=\"" vnx "\" opt=\"n\">", vdefSep)}
}}
}}
}}
# A sampe of what I'm trying to match:
#
# <sense id="n1.0" level="0" n="0" opt="n">
# <sense id="n1.1" level="1" n="I" opt="n">
# <sense id="n1.2" level="2" n="A" opt="n">
# <sense id="n1.3" level="2" n="B" opt="n">
# <sense id="n1.4" level="3" n="1" opt="n">
# <sense id="n1.5" level="3" n="2" opt="n">
# <sense id="n1.6" level="1" n="II" opt="n">
# <sense id="n1.7" level="2" n="A" opt="n">
# <sense id="n1.8" level="3" n="1" opt="n">
# <sense id="n1.9" level="3" n="2" opt="n">
# <sense id="n1.10" level="2" n="B" opt="n">
# <sense id="n1.11" level="3" n="1" opt="n">
# <sense id="n1.12" level="3" n="2" opt="n">
# <sense id="n1.12" level="3" n="2" opt="n">
# <sense id="n1.13" level="3" n="3" opt="n">
Basically, it goes through every single possibility that exists. There must be a better way.
Last edited by RudiC; 02-25-2018 at 02:37 PM..
Reason: Removed duplicated / edited paragraphs[
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02-25-2018
, I got that fixed (after 6hrs of droning at the comp). Maybe there is a very simple way, but none of the other offered solutions have worked so far, though I did learn new things from them. 
