Visit Our UNIX and Linux User Community

Full Discussion: Error when executing script
Operating Systems Linux Red Hat Error when executing script Post 302996993 by RudiC on Friday 5th of May 2017 05:09:23 AM
Old 05-05-2017
The -d option of date takes one single date only, not several separated by a line feed char. How about
Code:
D="$(stat -c %z sh* | awk -F"[ -]" '{print $3}')"
echo "$D"
03
03

This User Gave Thanks to RudiC For This Post:
 
Test Your Knowledge in Computers #245
Difficulty: Easy
In 1971, Ray Tomlinson, of BBN sent the first network e-mail.
True or False?

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

error while executing the script

Hello I am executing the following script nawk 'NR == 1 || substr($0,63,5) ~ /H... / && \ _++ == 2 { fn && close(fn); fn = "part_" ++c; _ = 1 } { print > fn }' sample.dat When i execute as it is it is executing fine. but when i execute the whole script as a single line like below ... (2 Replies)
Discussion started by: dsdev_123
2 Replies

2. Shell Programming and Scripting

Error while executing a script

My script is as below : #!/bin/sh for line in `cat Results.txt` do FEILD1=`echo $line |awk -F"|" '{print $1}'` FEILD2=`echo $line |awk -F"|" '{print $2}'` FEILD3=`echo $line |awk -F"|" '{print $3}'` FEILD4=`echo $line |awk -F"|" '{print $4}'` echo "$FEILD1 $FIELD2 $FIELD3 $FIELD4" done ... (15 Replies)
Discussion started by: shwetainnani
15 Replies

3. Shell Programming and Scripting

Error while executing the below script

I am executing the below in telnet #!/usr/bin/ksh File1=simple.txt # The file to check LogFile=simple.log # The log file DelayMax=30 # Timeout delay Tolerance=2 # BEGIN ############################## while true do StampNow=$(date +%s)/60 # stamp in minutes ... (3 Replies)
Discussion started by: chinniforu2003
3 Replies

4. UNIX for Dummies Questions & Answers

Error Executing the script.

Hi , I m getting an error after executing the script. My script. Script is used to find out the date on 8 different machines(mentioned in SERVERNAMES file). I have added public key to avoid ssh password and ssh without password working fine. #!/bin/sh fn_VMFind() { Date=`ssh -t... (5 Replies)
Discussion started by: pinga123
5 Replies

5. Shell Programming and Scripting

Error while executing a script

Hi Please assist. Im getting an error while execuing the script name d "cdsnd.basel.cd_new " as siiadm user. Thanks. siiadm> ls -l total 64 -rwxr-xr-x 1 siiadm sboadm 1004 Sep 17 2008 cdsnd.basel.cd -rwxr-xr-x 1 siiadm sapsys 998 Nov 16 09:14 cdsnd.basel.cd_new... (1 Reply)
Discussion started by: samsungsamsung
1 Replies

6. Shell Programming and Scripting

getting the error 'not found' while executing the script

Hi, I am not able to figure out what the problem is: getting the following error sqltst.sh: 1: not found here is the script #!/bin/sh . /home/dev1/.profile . /home/dev1/.infenv `sqlplus -s $REPDB_LOGON << EOF SET SERVEROUT ON SET FEEDBACK OFF SET HEADING OFF SET TRIMSPOOL... (4 Replies)
Discussion started by: svajhala
4 Replies

7. Shell Programming and Scripting

Error executing script

Please delete de thread. Thanks. (10 Replies)
Discussion started by: Rodrih92
10 Replies

8. Linux

Libssh2 error while executing script

hi all, i am getting libssh2 error while executing script in RHEL 6, when i locate that file its not there below is the ouput of this # locate libssh2_agent_init # cat /etc/issue Red Hat Enterprise Linux Server release 6.1 (Santiago) Kernel \r on an \m how do i resolve this issue, i... (1 Reply)
Discussion started by: muzaffar.k
1 Replies

9. UNIX for Dummies Questions & Answers

Error executing the script

I have the following script test.sh owned by dwdev account and group dwdev, the permissions on the script are as follows. -rw-r-x--- 1 dwdev dwdev 279 Sep 17 13:19 test.sh Groups: cat /etc/group | grep dwdev dwdev:x:704:dwdev dwgroup:x:725:dwdev writers:x:726:dwdev User: cat /etc/passwd |... (3 Replies)
Discussion started by: Ariean
3 Replies

10. Shell Programming and Scripting

Gettting error while executing script

getting error as below while executing script in linux. OS version: Linux VGP-3GPSDB-LX 3.10.0-514.el7.x86_64 #1 SMP Wed Oct 19 11:24:13 EDT 2016 x86_64 x86_64 x86_64 GNU/Linux ./imxtract.sh: line 395: unexpected EOF while looking for matching ``' ./imxtract.sh: line 402: syntax error:... (1 Reply)
Discussion started by: Riverstone
1 Replies
DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)

Featured Tech Videos

All times are GMT -4. The time now is 07:50 AM.
Unix & Linux Forums Content Copyright 1993-2020. All Rights Reserved.
Privacy Policy