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Full Discussion: Error when executing script
Operating Systems Linux Red Hat Error when executing script Post 302996992 by anaigini45 on Friday 5th of May 2017 05:03:25 AM
Old 05-05-2017
I have another question on command substitution.
The same script, but different command substitution.

I simply run this command from the terminal :

[root@L28tstream1 emokheng]# stat -c %z * | awk '{print $1}'
[root@L28tstream1 emokheng]#

As you see, I get the dates of the file generated in the directory.

However, when I attempt to use this command as a substitute, like this, I get a diferent output :

[root@L28tstream1 emokheng]# D=$(stat -c %z * | awk '{print $1}')
[root@L28tstream1 emokheng]# echo $D
2015-08-18 2015-08-18

It all displays in one line. Why is this, and how do I get it to display in two separate lines like the command above this?

Actually the main output I want is to get ONLY the day section of the whole date. Means I want to extract only '18' from 2015-08-18. This is for all the files in the directory.
Therefore, I use this command :

[root@L28tstream1 emokheng]# FDAY=$(date -d "$D" '+%d')
date: invalid date `2015-08-18\n2015-08-18'
[root@L28tstream1 emokheng]#

However, as you can see, the error is shown. Perhaps if
echo $D

displays two separate lines, the error above will not happen?

How do I display ONLY the day part of the whole date for a file in a directory?

Last edited by anaigini45; 05-05-2017 at 06:12 AM..
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