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Full Discussion: IP Range Assigning
Homework and Emergencies Homework & Coursework Questions IP Range Assigning Post 302974532 by TryllZ on Tuesday 31st of May 2016 12:34:52 PM
Old 05-31-2016
IP Range Assigning

THIS IS A SAMPLE PRACTICAL EXAM QUESTION, COMPLETE FILE HAS BEEN ATTACHED AS WELL.

Hi All,
I'm a bit confused about assigning IP address from IP Ranges.
I am using this scenario below to understand.
Scenario
Adatum.com an international IT solutions company, is launching 12 new branches in a new country where they currently have no existing branches. The sWin CIO has asked that each subnet should host at least 1000 devices.
sWin has obtained a network address of 192.168.0.0/18. This address needs to be subnetted further. The internal subnet mask will be /22
The company's subnet plan allows for:
- Router Pool: 2 router interfaces for each subnet - the first 2 IP addresses from each subnet.
- Managed Network Device Pool: The first 20 IP addresses that follow the Router Pool are reserved for switches and other network devices
- Server Pool: The first 20 IP addresses following the Managed Network Device Pool are reserved for servers.
- Workstation Static Pool: The first 10 IP addresses following the Server Pool are reserved for Workstations that require static IP addresses.
- Workstation DHCP Pool: The remaining IP addresses are reserved for automatic IP configuration
You have been asked to use subnet 9 for your device addressing.
Configure the first IP address from the Server Pool to Lon-DC1.
Configure the first IP address from the Workstation Static Pool to sWinPC1.
Configure the first IP address from the Router Pool to be the default gateway.

So I have the IP address range as such:
192.168.0.0 is the Network ID and 192.168.3.255 is the Broadcast address.
Now can some one explain me how the IP ranges will be assigned having found the IP ranges being that since the last borrowed bit is place holder of 4 the IP ranges will also be in 4, for example 192.168.0.0 - 192.168.0.3, which means that if I use the 9th subnet the IP Range is 192.68.0.32 - 192.168.0.35, however my teacher has explained me (which I did not understand for some reason) in a way that IP range 9th subnet will be 192.168.32.1 etc..
I'm confused as to when to use my method for IP ranges and when to use my teachers.

My basic question is how to know when does the subnet range changes and which is the subnet range the first one of the teacher method.
Please, Thank You

University Of Swinburne , Kuching, Malaysia, Bachelors in Information Communication Technology Networking Major, Second Year, Professor Mujahid, Bachelor of Information and Communication Technology | Swinburne University of Technology Sarawak Campus
 

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PRIPS(1)						    BSD General Commands Manual 						  PRIPS(1)

NAME
prips -- print the IP addresses in a given range SYNOPSIS
prips [-c] [-d delim] [-e exclude] [-f format] [-i incr] start end prips [-c] [-d delim] [-e exclude] [-f format] [-i incr] CIDR-block prips -h DESCRIPTION
The prips tool can be used to print all of the IP addresses in a given range. It can enhance tools that only work on one host at a time, e.g. whois(1). The prips tool accepts the following command-line options: -c Print the range in CIDR notation. -d delim Set the delimiter to the character with ASCII code delim where 0 <= delim <= 255. -e <x.x.x,x.x> Exclude ranges from the output. -f format Set the format of addresses (hex, dec, or dot). -h Show summary of options. -i incr Set the increment to 'x'. ENVIRONMENT
The prips tool's operation is not influenced by any environment variables. FILES
The prips tool's operation is not influenced by any files. EXAMPLES
Display all the addresses in a reserved subnet: prips 192.168.32.0 192.168.32.255 The same, using CIDR notation: prips 192.168.32/24 Display only the usable addresses in a class A reserved subnet using a space instead of a newline for a delimiter: prips -d 32 10.0.0.1 10.255.255.255 Display every fourth address in a weird block: prips -i 4 192.168.32.7 192.168.33.5 Determine the smallest CIDR block containing two addresses: prips -c 192.168.32.5 192.168.32.11 DIAGNOSTICS
The prips utility exits 0 on success, and >0 if an error occurs. SEE ALSO
ipsc(1), gipsc(1) STANDARDS
No standards were harmed in the writing of the prips tool. HISTORY
The prips tool was originally written by Daniel Kelly and later adopted by Peter Pentchev. This manual page was originally written by Juan Alvarez for the Debian GNU/Linux system and later added to the prips distribution and converted to mdoc format by Peter Pentchev. AUTHORS
Daniel Kelly <dan@vertekcorp.com> Juan Alvarez <jalvarez@fluidsignal.com> Peter Pentchev <roam@ringlet.net> BUGS
Please report any bugs in the prips tool to its current maintainer, Peter Pentchev. BSD
March 1, 2011 BSD
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