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Top Forums Shell Programming and Scripting Issue using empty variable in grep command Post 302956432 by mbak on Tuesday 29th of September 2015 11:54:11 PM
Old 09-30-2015
Thanks Jim for your response, here is what I'm trying to do, there is a particular disk of certain size in /tmp/list.out that I want to exclude and below is my actual script, it works fine when there is a value for variable DSK otherwise it does nothing if /tmp/list.out is empty i.e., if variable $DSK is empty and I want to continue with the script irrespective of data present in /tmp/list.out since there could other disks that has a failed path.

Code:
DSK=$( awk '/disk/ {print substr($1, 7)}' /tmp/list.out )
for i in `lspv | awk '{print$1}' |grep -v "$DSK"`
 do
  DSK_PATH=`lspath | grep -w $i | grep Ena | wc -l`
  if [ "$DSK_PATH" -lt 2 ]
  then
        echo "Failed path found"
  else
        echo "No failed path"
  fi
 done
fi


Last edited by mbak; 09-30-2015 at 12:57 AM.. Reason: added code tags
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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