09-20-2015
Difference between inbuilt suid programs and user defined root suid programs under bash shell?
Hey guys,
Suppose i run passwd via bash shell. It is a suid program, which temporarily runs as root(owner) and modifies the user entries.
However, when i write a C file and give 4755 permission and root ownership to the 'a.out' file , it doesn't run as root in bash shell. I verified this by comparing uid and euid within the program which turned out to be the same. However, in zsh shell, it runs with root privileges
My question is : Why does an inbuilt program like suid is able to run with root privileges in bash shell while a user defined suid root program is not ?
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elksemu(1) General Commands Manual elksemu(1)
NAME
elksemu - Embedded Linux Kernel Subset emulator
SYNOPSIS
/lib/elksemu program [arguments]
DESCRIPTION
Elksemu is a program that allows 8086 ELKS programs to be run under Linux-i386. These programs can be compiled using the bcc(1) C compiler.
It is not usual to invoke /lib/elksemu directly, either the simple patch or kernel module distributed with it will cause the kernel to run
/lib/elksemu with the correct arguments whenever the user tries to execute an ELKS executable directly.
OPTIONS
There are no flag options to elksemu, the first argument is the name of the program to run the rest are arguments that are passed to the
Elks program.
The elksemu program is normally installed suid-root and in this event it is able to run execute only (chmod 111) elks executables and act
correctly on the suid permission bits on those executable. This may be considered a security hazard so elksemu does not have to be
installed suid-root.
SEE ALSO
bcc(1), as86(1), ld86(1)
BUGS
Elksemu is incomplete.
The program may still have security bugs!
Jan, 1997 elksemu(1)