Passing variable as input & storing output in other variable
I have a below syntax its working fine...
Im getting expected output as below:
Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results to be stored in a variable called as logdata
now my aganda is to store the output in a variables instead of storing output in a file. I have created a code but I m getting unexpected results & since last 2hrs I got stuck up with this
Last edited by Don Cragun; 09-06-2015 at 11:47 AM..
Reason: Change PHP tags to CODE tags.
HI
I am trying to store the output of this awk command
awk -F, {(if NR==2) print $1} test.sr
in a variable when I am trying v= awk -F, {(if NR==2) print $1} test.sr
$v = awk -F, {(if NR==2) print $1} test.sr
but its not working out .
Any suggestions
Thanks
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