Script doesn't print error. Post: 302943048

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Top Forums Shell Programming and Scripting Script doesn't print error. Post 302943048 by Don Cragun on Tuesday 5th of May 2015 01:29:52 AM

05-05-2015

Registered User

Maybe something like this comes closer to what you're trying to do:

Code:

#!/bin/ksh
IAm=${0##*/}
file=
while getopts :f: arg
do
        case $arg in
	(f)	file="$OPTARG"
		printf 'Found -f option; setting file="%s"\n' "$file";;
	(\?)	printf 'Usage: %s -f file operand...\n' "$IAm" >&2
		exit 1;;
        esac
done
shift $((OPTIND - 1))
if [ "$file" = "" ]
then	printf '%s: No "-f file" option found.\n' "$IAm" >&2
	exit 2
else	printf 'Last "-f file" option set file to "%s"\n' "$file"
fi
printf 'Operands remaining after option parsing:\n'
printf '\t"%s"\n' "$@"

Note, however, that it is more common to use an operand (rather than an option) to specify a mandatory utility argument.

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