I need a command that will print each line of a text file UNLESS the 3rd field of that line is equal to the number 999. (space seperated fields)
Solaris10/BASH SHELL:
INPUT.TXT OUTPUT.TXT
The INPUT.TXT file might have 5 or 10 fields, but it is field 3=999 that I dont want. I'm hoping there is a bash shell command (awk?) that could do this.
Thank you so very much!
Take cares!
-aj
Last edited by Scrutinizer; 11-06-2014 at 03:16 PM..
Reason: Added code tags
Hi All,
I need a code to print those lines where there's NO indents on the 1st field
Example shown below.
I tried to use the below codes but i am not able to see the expected result.
Can any expert give any advise ?
My Code
cat filename| awk '$1 ~ /^+$/ {print $0}'
Input
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