Hi
i need a help for making a script whch can print next line if it matches a particular word
like file1 have
ename Mohan
eid 2008
ename Shyam
eid 345
if scipt got Mohan it will print next line (eid 2008)
pls help me .......:) (2 Replies)
Hi All,
I would like my code to be able to print out the whole line if 1st field has a dot in the number. Sample input and expected output given below.
My AWK code is below but it can;t work, can any expert help me ?
Thanks in advance.
{if ($1 ~ /*\.*/) { print $0 }}
Input:
... (2 Replies)
Hi all,
I got several lines line this
a b c d e 1 e
a 1 c d e 3 f
a b c 1 e 8 h
a b c d e 1 w
a 1 c d e 2 w
a b c d e 1 t
a b c d e 7 4
How can I print the line if 1 is the field one before the last field?
Basicly this 2 field ?
a b c d e 1 e
a b c d e 1 t
The file I got is... (7 Replies)
Hi Folks!
im printing all lines where the characters in position 270-271 match 33|H1|HA|KA|26 so i came up with this
#!/bin/bash
array=(33 H1 HA KA 26 )
for i in "${array}"
do
#echo $i
awk '{ if (substr($0,270,2)~'/$i/') print; }' $1 >> $1.temp
done
It works fine . but... (2 Replies)
I'm using sh on hp-ux and want to find / print a line that matches 132.101- and the next line, too. grep -A isn't supported on hp-ux, so I'm trying awk and sed.
The code below works but only prints the first occurence. I need all matches from the file.
awk... (2 Replies)
Good day,
I have a list of regular expressions in file1. For each match in file2, print the containing line and the line after.
file1:
file2:
Output:
I can match a regex and print the line and line after
awk '{lines = $0} /Macrosiphum_rosae/ {print lines ; print lines } '
... (1 Reply)
Hi,
I could only find examples to print line before/after a match, but I'd need to print line after two separate lines matching.
E.g.: From the below log entry, I would need to print out the 1234. This is from a huge log file, that has a lot of entries with "CLIENT" and "No" entries (+ other... (3 Replies)
Hi
I want to extend following command so that on the basis of "Branch: ****" on the third line I can grep and print name of the file on the first line.
cat .labellog.emd | grep DA2458A7962276A7E040E50A0DC06459 | cut -d " " -f2 | grep -v branch_name | xargs -I file <command to describe> file
... (1 Reply)
Der colleagues,
4 days I am trying to solve my issue and no success..
Maybe you can give me a clue how to achieve what I need..
So I have two files.
file1 example:
1_column1.1 1_column2.1 aaa 1_column4.1
1_column1.2 1_column2.2 ttt 1_column4.2
1_column1.3 1_column2.3 ... (10 Replies)