Top Forums Shell Programming and Scripting Print lines before after pattern meacted Post 302902038 by Optimus81 on Saturday 17th of May 2014 05:06:40 PM
Print lines before after pattern meacted

Hi All,

Am trying to print pervious lines of the pattern matched, I was able to print pattern matched and the required data but don't know how to get the pervious line.


Code:
 ifconfig -a | grep  10.118.67.33 | sed -e 's/^[[: :]]*//' -e 's/[[: :]]*$//' | awk '{FS=" "; print $6}'

output I get is the ipaddress ie,
Code:
 10.118.67.33

what am looking is how to get the pervious line of this ipaddress... can someone please help me on this.


Many thanks
Ops
 
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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD

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