Sponsored Content
Full Discussion: Shell script - group by
Top Forums Shell Programming and Scripting Shell script - group by Post 302900198 by baladelaware73 on Monday 5th of May 2014 11:32:48 AM
Old 05-05-2014
Lightbulb

Thanks, this is a great approach. It worked for me.
 

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

HELP! Group by in shell script (awk/sed?)

Hello, Could some expert soul please help me with this? I have following file format - task time abc 5 xyz 4 abc 5 xyz 3 ddd 10 ddd 2 I need to generate output as - task ... (5 Replies)
Discussion started by: sncoupons
5 Replies

2. Shell Programming and Scripting

Shell script to rename a group of files

Hello, I am having 1800 files in a directory with a specified format, like amms_850o_prod.000003uNy amms_850o_prod.000003u8x amms_850o_prod.000003taP amms_850o_prod.000003tKy amms_850o_prod.000003si4 amms_850o_prod.000003sTP amms_850o_prod.000003sBg amms_850o_prod.000003rvx... (12 Replies)
Discussion started by: atlantis
12 Replies

3. Shell Programming and Scripting

"group by" using shell script?

not sure if it's called "group by" , but what i'm going to do is like this: i have a file below: 192.168.1.10 192.168.1.10 192.168.1.10 192.168.1.11 192.168.1.15 192.168.1.15 192.168.1.20 192.168.1.22 then i hope to get the result like this: 192.168.1.10 : 3 192.168.1.11 : 1... (6 Replies)
Discussion started by: tiger2000
6 Replies

4. Solaris

su: No shell/No directory! if sys is added to a users secondary group

Hi, When I include a user to the secondary group "sys" GID=3 in Solaris 9 OS I'm not able to login. I get these error. The user home directory and the shell exists. Is this because of any security hardening. # su - agent No directory! # su agent su: No shell # grep taddm /etc/passwd... (14 Replies)
Discussion started by: agent001
14 Replies

5. Shell Programming and Scripting

Shell Script to ignore # and take corresponding user and group

Hi, I have a following file: role.IMPACT_USER.user=admin role.IMPACT_USER.user=dd12345 role.IMPACT_USER.user=ss76767 #role.IMPACT_USER.user=root #role.IMPACT_USER.group=System role.IMPACT_USER.group=ImpactUser #Description: Allow users to login in to Impact, start and stop service... (5 Replies)
Discussion started by: dbashyam
5 Replies

6. Shell Programming and Scripting

Help Linux Shell Group exists

I am having some problems when writing shell as follows: shell runs but returns no results echo "enter group name: " dir="/home" read group if id -g $group > /dev/null 2>&1 then echo "group exits" else echo... (6 Replies)
Discussion started by: kingkner
6 Replies

7. Shell Programming and Scripting

Help me to perform count & group by operation in shell scripting?

Hi All, I want to display the distinct values in the file and for each distinct value how may occurance or there. Test data: test1.dat 20121105 20121105 20121105 20121105 20121106 20121106 20121106 20121105 I need to display the output like Output (2 Replies)
Discussion started by: bbc17484
2 Replies

8. Shell Programming and Scripting

Shell Script to Group by Based on Multiple Fields in a file

Hi, I want to know if there is any simple approach to SUM a field based on group by of different fields for e.g. file1.txt contains below data 20160622|XXX1||50.00||50.00|MONEY|Plan1| 20160622|XXX1||100.00||100.00|MONEY|Plan1| 20160623|XXX1||25.00||25.00|MONEY|Plan1|... (3 Replies)
Discussion started by: cnu_theprince
3 Replies

9. Shell Programming and Scripting

Emulate group-by in shell script

Hello All, I saw this problem on one of the forum and solved it using group-by in oracle sql, though I am a bit curious to implement it using shell script : There is a file having number of operations : Opeation,Time-Taken operation1,83621 operation2,72321 operation3,13288... (11 Replies)
Discussion started by: mukulverma2408
11 Replies
uudemon(4)						     Kernel Interfaces Manual							uudemon(4)

NAME
uudemon.admin, uudemon.cleanu, uudemon.hour, uudemon.poll - Administrative shell scripts for polling remote systems, cleaning up spool directories, reporting status to the system administrator, and routine invocations of the uuxqt and uusched daemons SYNOPSIS
These shell scripts reside in the following directory: /usr/lib/uucp DESCRIPTION
All the scripts can be run from the command line or can be run automatically by the cron daemon. To automatically run the scripts, remove the comment character (#) from the beginning of the relevant line in the /var/spool/cron/crontabs/uucp file. This script reports status to the system administrator. It issues the uustat command to find out the status of uucp jobs. It mails the results to the uucp login ID. The script may be modified to send mail to any login ID such as the uucp administrative login ID (uucpa) or root. This script cleans up the /var/spool/uucp and /var/spool/uucppublic directories by running the uucleanup command. The uucleanup com- mand is run with the following parameters: -C7, -D7, X2, -o2, -W1. This script runs the uusched and uuxqt daemons in the background. This script polls the systems listed in the /usr/lib/uucp/Poll file. The uudemon.poll script should be scheduled before the uudemon.hour script. This allows uudemon.poll to create any command files before cron runs the uudemon.hour script. FILES
Contains the uudemon.admin, uudemon.cleanu, uudemon.hour and uudemon.poll files. Contains the uucp file. RELATED INFORMATION
Commands: cron(8), uucleanup(8), uusched(8), uuxqt(1) Files: /usr/lib/uucp delim off uudemon(4)
All times are GMT -4. The time now is 02:16 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy