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Full Discussion: Regex matching with grep -l
Top Forums UNIX for Dummies Questions & Answers Regex matching with grep -l Post 302851769 by newbie2010 on Monday 9th of September 2013 03:27:23 PM
Old 09-09-2013
Regex matching with grep -l

I am trying to find patterns in files using grep -l -e. I specifically am searching for abc. I want any file that has abc in it, but not just the letters abc. I am searching for a pattern a followed by b followed by c. I have tried egrep -l and also I have tried the following:

Code:
grep -el '\(abc\)\$'

This will return abc but if there are more characters it will return those too.

I have patterns such as the following
Code:
abc_vol12
abc_vol13
abc_vol15

in with other patterns and I want only these to be selected (found). In addition I was trying to find out how to negate the search. Not sure if grep is the right tool for this.
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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